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From: James Kuyper <jameskuyper@alumni.caltech.edu>
Newsgroups: comp.lang.c
Subject: Re: "A diagram of C23 basic types"
Date: Mon, 7 Apr 2025 14:35:52 -0400
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On 4/3/25 18:00, Waldek Hebisch wrote:
> Tim Rentsch <tr.17687@z991.linuxsc.com> wrote:
....
>> Not always practical.  A good example is the type size_t.  If a
>> function takes an argument of type size_t, then the symbol size_t
>> should be defined, no matter which header the function is being
>> declared in.
> 
> Why?  One can use a type without a name for such type.

How would you declare a pointer to a function type such that it is
compatible with such a function's type?
When a variable is needed to store a value that would be passed as the
size_t argument to such a function, I would (in the absence of any
specific reason to do otherwise) want to declare that object to have the
type size_t.
Why should I have to #include a different header just because I want to
do these things?