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Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: Richard Heathfield <rjh@cpax.org.uk> Newsgroups: comp.theory Subject: Re: Cantor Diagonal Proof Date: Wed, 9 Apr 2025 17:32:30 +0100 Organization: Fix this later Lines: 90 Message-ID: <vt67eu$10han$2@dont-email.me> References: <vt3dg5$1qj4p$1@dont-email.me> <vt3eme$2bi5g$2@dont-email.me> <vt3qqn$1qj4q$1@dont-email.me> <1ab7fe6b234496769adde06995790eebb827756e.camel@gmail.com> <vt5qac$j4kv$1@dont-email.me> <60cbb326c7d65b1bbd9451319bd07721c76d307f.camel@gmail.com> <vt61cc$putp$1@dont-email.me> <a3088f983cc8deed93d9cef50aaaaeb0f0be0aa3.camel@gmail.com> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Wed, 09 Apr 2025 18:32:31 +0200 (CEST) Injection-Info: dont-email.me; posting-host="a0bfded38ff50eae03c6cf4454ca917e"; logging-data="1066327"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19wZ5OX+CkjR/kmpba1oiuiaWSpmo7AN1U35ryKMwJSYA==" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:B7bu1q5jScQlnynSiAjjzfF1JZg= In-Reply-To: <a3088f983cc8deed93d9cef50aaaaeb0f0be0aa3.camel@gmail.com> Content-Language: en-GB On 09/04/2025 17:08, wij wrote: > On Wed, 2025-04-09 at 15:48 +0100, Richard Heathfield wrote: >> On 09/04/2025 15:31, wij wrote: >>> On Wed, 2025-04-09 at 13:48 +0100, Richard Heathfield wrote: >>>> On 09/04/2025 13:25, wij wrote: >>>>> On Tue, 2025-04-08 at 19:44 +0100, Andy Walker wrote: >>>>>> On 08/04/2025 16:17, Richard Heathfield wrote: >>>>>>> It will, however, take me some extraordinarily convincing >>>>>>> mathematics before I'll be ready to accept that 1/3 is irrational. >>>>>> >>>>>> I don't think that's quite what Wij is claiming. He thinks, >>>>>> rather, that 0.333... is different from 1/3. No matter how far you >>>>>> pursue that sequence, you have a number that is slightly less than >>>>>> 1/3. In real analysis, the limit is 1/3 exactly. In Wij-analysis, >>>>>> limits don't exist [as I understand it], because he doesn't accept >>>>>> that there are no infinitesimals. It's like those who dispute that >>>>>> 0.999... == 1 [exactly], and when challenged to produce a number >>>>>> between 0.999... and 1, produce 0.999...5. They have a point, as >>>>>> the Archimedean axiom is not one of the things that gets mentioned >>>>>> much at school or in many undergrad courses, and it seems like an >>>>>> arbitrary and unnecessary addition to the rules. But we have no good >>>>>> and widely-known notation for what can follow a "...", so the Wijs of >>>>>> this world get mocked. He doesn't help himself by refusing to learn >>>>>> about the existing non-standard systems. >>>>> >>>>> Lots of excuses like POOH. You cannot hide the fact that you don't have a >>>>> valid proof in those kinds of argument. >>>>> If you propose a proof, be sure you checked against the file I provided. >>>>> I have no no time for garbage talk. >>>> >>>> I have read that document, about which I have a simple question. >>>> >>>> From Theorem 2 and Axiom 2, if x can be expressed in the form of >>>> p/q, then p and q will be infinite numbers (non-natural numbers). >>>> Therefore, x is not a rational number. And since a non-rational >>>> number is an irrational number, the proposition is proved. >>>> >>>> Let p = 1 >>>> Let q = 3 >>>> >>>> Is it or is it not your contention that p and q are "infinite" >>>> (non-natural) numbers? >>> >>> The audience of the file was originally intended to include 12 years old kids. >>> Wordings in the file wont' be precise enough to meet rigorous requirements. >>> The mentioned paragraph was revised (along with several others): >>> >>> Theorem 2: ℚ+ℚ=ℚ (the sum of a rational number and a rational number is still a >>> rational number), but it is only true for finite addition steps. >>> Proof: Let Q'={p/q| p,q∈ℕ, q≠0 and p/q>0}, then Q'⊂ℚ. Since the sum of any two >>> terms in Q' is greater than the individual terms, the sum q of the >>> infinite terms (q=q₁+q₂+q₃...) is not a fixed number. >>> >>> What I intended to mean is: 0.999...= 999.../1000... (in p/q form) >>> Since p,q will be infinitely long to denote/define 0.999..., p,q won't be >>> natural numbers. Thus, "ℚ+ℚ=ℚ" is conditionally true (so false). >>> >>> But I still think your English is worse than olcott's (and mine). >> >> Charmed, I'm sure. >> >>>> Prediction: you will evade the question. Why not surprise me? >>> Ok, I evade more clarification. >> >> I deduce from what you intended to mean (and that's very classy >> English, so well done you) that you didn't intend to mean that 1 >> and 3 are "infinite". >> >> And you're right. 1 and 3 are both integers. Natural numbers. >> Whole numbers. Finite numbers. Not infinite. >> >> Let us calculate the ratio of these two integers, 1/3. Oh look, >> it's 0.3r. So 0.3r is the ratio of two integers (i.e. rational) >> after all. Quelle surprise! > > The correct equality is 1/3= 0.333... + nonzero_remainder. Keep on dividing the remainder, and what do you get? Oh look! More 3s. > If you use it to prove, that proof never finishes. Thus, invalid. And Achilles never catches the tortoise. Yeah, right. -- Richard Heathfield Email: rjh at cpax dot org dot uk "Usenet is a strange place" - dmr 29 July 1999 Sig line 4 vacant - apply within