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From: dbush <dbush.mobile@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD simulated by HHH cannot possibly halt (Halting Problem) ---
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Date: Sun, 13 Apr 2025 17:03:18 -0400
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On 4/13/2025 5:00 PM, olcott wrote:
> On 4/13/2025 3:00 PM, dbush wrote:
>> On 4/13/2025 3:59 PM, olcott wrote:
>>> On 4/13/2025 3:54 AM, joes wrote:
>>>> Am Fri, 11 Apr 2025 10:56:32 -0500 schrieb olcott:
>>>>> On 4/11/2025 3:24 AM, Richard Heathfield wrote:
>>>>>> On 11/04/2025 08:57, Mikko wrote:
>>>>
>>>>>>> No proof of this principle has been shown so its use is not valid.
>>>>>>
>>>>>> No proof of Peano's axioms or Euclid's fifth postulate has been 
>>>>>> shown.
>>>>>> That doesn't mean we can't use them.
>>>>>> Mr Olcott can have his principle if he likes, but only by EITHER
>>>>>> proving it (which, as you say, he has not yet done) OR by taking 
>>>>>> it as
>>>>>> axiomatic, leaving the world of mainstream computer science behind 
>>>>>> him,
>>>>>> constructing his own computational 'geometry' so to speak, and
>>>>>> abandoning any claim to having overturned the Halting Problem. Navel
>>>>>> contemplation beckons.
>>>>>> Axioms are all very well, and he's free to invent as many as he 
>>>>>> wishes,
>>>>>> but nobody else is obliged to accept them.
>>>>>>
>>>>> *Simulating termination analyzer Principle*
>>>>> It is always correct for any simulating termination analyzer to stop
>>>>> simulating and reject any input that would otherwise prevent its own
>>>>> termination.
>>>> Sure. Why doesn’t the STA simulate itself rejecting its input?
>>>>
>>>
>>> Because that is a STUPID idea and categorically impossible
>>> because the outermost HHH sees its needs to stop simulating
>>> before any inner HHH can possibly see this.
>>>
>>
>> In other words, you agree that Linz and others are correct that no H 
>> exists that satisfies these requirements:
>>
>>
>> Given any algorithm (i.e. a fixed immutable sequence of instructions) 
>> X described as <X> with input Y:
>>
>> A solution to the halting problem is an algorithm H that computes the 
>> following mapping:
>>
>> (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
>> (<X>,Y) maps to 0 if and only if X(Y) does not halt when executed 
>> directly
>>
> 
> No stupid! Those freaking requirements are wrong 

In other words, you have no interest in something that would make all 
truth provable.