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Path: ...!news.nobody.at!weretis.net!feeder8.news.weretis.net!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Luigi Fortunati <fortunati.luigi@gmail.com> Newsgroups: sci.physics.research Subject: The spring Date: Thu, 17 Apr 2025 09:40:06 PDT Organization: A noiseless patient Spider Lines: 25 Approved: Jonathan Thornburg [remove -color to reply]" <dr.j.thornburg@gmail-pink.com (sci.physics.research) Message-ID: <vtqnao$gtk3$1@dont-email.me> Reply-To: fortunati.luigi@gmail.com X-Trace: individual.net UGpIGfRbAFvaRHe5sfaXGwX8UJvCqZ8IycBUCmsZcLm16e8dHLdS+BNKb8 Cancel-Lock: sha1:qNlxrh7Mgsd3Oc4oZNOwAZDKRgE= sha256:EJbXazXnjf5Qc0PA75Aq4bMmSjKMfgRIxZzMmdPdUoY= X-Forwarded-Encrypted: i=2; AJvYcCV4XimgUwzLqoGol/Mo1zwZ6oCielVHS4ciPq6xUO5g4YYqDlH4o5n02h78iLi+yYV1QHftbFD8AsHzLBS1+g==@gmail.com X-Auth-Sender: U2FsdGVkX1+lJO7ZutWGzeOMcdbUxfhSWzntB4K+tFkuw7EjVehgwybeqYwD5UCt X-ICQ: 1931503972 Bytes: 1924 The spring AB is a body. If I exert the force F on the end A, the spring accelerates according to Newton's second law F=ma and contracts with respect to its length at rest. Why is there this contraction if there is no opposing force on the other side of the spring? Or perhaps, there is an opposing force? Luigi Fortunati [[Mod. note -- There are two possibilities: If the spring is *massless* (obviously this is an idealization, but it's a useful case for conceptual purposes), then the spring doesn't contract (it just accelerates as a rigid body), since as you notes thereis no opposing force on the other side of the spring. If the spring has *nonzero mass*, then the inertia of the various parts of the spring provides the opposing force. To work this out in detail we'd need to write out equations of motion (Newton's 2nd law + Hooke's law) for the individual parts of the spring, then solve these equations. -- jt]]