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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: HHH(DD) --- COMPUTE ACTUAL MAPPING FROM INPUT TO OUTPUT --- Using
 Finite String Transformations
Date: Thu, 24 Apr 2025 14:45:31 -0500
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On 4/24/2025 2:15 PM, Fred. Zwarts wrote:
> Op 24.apr.2025 om 19:46 schreef olcott:
>> On 4/24/2025 3:11 AM, Fred. Zwarts wrote:
>>> Op 24.apr.2025 om 05:34 schreef olcott:
>>>> On 4/23/2025 7:31 PM, Mike Terry wrote:
>>>>> On 23/04/2025 16:38, olcott wrote:
>>>>>> On 4/23/2025 10:28 AM, Mike Terry wrote:
>>>>>>> On 23/04/2025 10:02, Fred. Zwarts wrote:
>>>>>>>> Op 22.apr.2025 om 21:50 schreef olcott:
>>>>>>>>> On 4/22/2025 2:30 PM, Fred. Zwarts wrote:
>>>>>>>>>> Op 22.apr.2025 om 21:14 schreef olcott:
>>>>>>>>>>> On 4/22/2025 1:10 PM, Fred. Zwarts wrote:
>>>>>>>>>>>> Op 22.apr.2025 om 18:38 schreef olcott:
>>>>>>>>>>>>>
>>>>>>>>>>>>> a function is computable if there exists an algorithm
>>>>>>>>>>>>> that can do the job of the function, i.e. given an input
>>>>>>>>>>>>> of the function domain it can return the corresponding output.
>>>>>>>>>>>>> https://en.wikipedia.org/wiki/Computable_function
>>>>>>>>>>>>>
>>>>>>>>>>>>> On Turing Machines inputs <are> finite strings, and
>>>>>>>>>>>>> finite string transformation rules <are> applied to
>>>>>>>>>>>>> these finite strings to derive corresponding outputs.
>>>>>>>>>>>>>
>>>>>>>>>>>> And it has been proven that no finite string transformations 
>>>>>>>>>>>> are possible that report the halting behaviour for all 
>>>>>>>>>>>> inputs that specify a correct program. 
>>>>>>>>>>>
>>>>>>>>>>> int sum(int x, int y) { return x + y; }
>>>>>>>>>>> Only when people stupid assume the same thing as
>>>>>>>>>>> sum(3,2) should return the sum of 5 + 3.
>>>>>>>>>>>
>>>>>>>>>> Therefore HHH should report on the actual input, the finite 
>>>>>>>>>> string that describes a halting program. Not on the 
>>>>>>>>>> hypothetical input that does not halt, because it is based on 
>>>>>>>>>> a hypothetical HHH that does not abort.
>>>>>>>>>>
>>>>>>>>>> Why do you maintain that HHH should process the hypothetical 
>>>>>>>>>> input instead of the actual input.
>>>>>>>>>> Do you really believe that 3+2 equals 5+3?
>>>>>>>>>
>>>>>>>>> I have proven that the directly executed DD and DD
>>>>>>>>> emulated by HHH according to the semantics of the
>>>>>>>>> x86 language have a different set of state changes
>>>>>>>>> many hundreds of times for several years.
>>>>>>>> You never showed a proof. You only repeated a dream. You are 
>>>>>>>> dreaming many years without any logic. You failed to show the 
>>>>>>>> first state change where the direct execution is different from 
>>>>>>>> the simulation. You only showed an erroneous HHH that fails to 
>>>>>>>> reach the end of the simulation of a halting program.
>>>>>>>
>>>>>>> Worse than this, on more than one occasion I've actually posted 
>>>>>>> traces of computation DDD(DDD) executed directly and simulated by 
>>>>>>> HHH side by side.  Both traces were of course /identical/, up to 
>>>>>>> the point where HHH stops simulating. 
>>>>>>
>>>>>> *Factually incorrect* (You are usually very careful about these 
>>>>>> things)
>>>>>> The call to HHH(DD) from the directly executed DD returns.
>>>>>> The call to HHH(DD) from DD emulated by HHH cannot possibly return.
>>>>>>
>>>>>
>>>>> ...because HHH stops simulating before reaching that step in the 
>>>>> computation.  Note that I said
>>>>>
>>>>> MT:  Both traces were of course /identical/,
>>>>>       *up to the point where HHH stops simulating*
>>>>>
>>>>> So I was factually correct.
>>>>>
>>>>>
>>>>> Mike.
>>>>>
>>>>
>>>> It *is not* up to the point where HHH stops simulating.
>>>>
>>>> It is up to the point where the simulated versus directly
>>>> executed calls HHH(DD).
>>>>
>>> That is exactly the same point. If not, show the difference in the 
>>> traces before that point.
>>
>> As soon as the directly executed DD calls HHH(DD) this
>> call immediately returns.
>>
>> When DD emulated by HHH calls HHH(DD) then HHH emulates
>> DD and also emulates itself emulating DD. This is one
>> whole recursive emulation than the directly executed
>> DD can possibly get to.
> Again a lot of words, which hide that you cannot show where the traces 
> differ up to that point.

THEY DIFFER BY THE EMULATED DD REACHES RECURSIVE EMULATION
AND THE DIRECTLY EXECUTED DD NEVER DOES.

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer