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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_Computable_Functions_---_finite_string_transformati?=
 =?UTF-8?Q?on_rules_---_0_=E2=89=A01?=
Date: Thu, 24 Apr 2025 18:58:35 -0500
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On 4/24/2025 6:14 PM, Richard Damon wrote:
> On 4/24/25 5:13 PM, olcott wrote:
>> On 4/24/2025 5:59 AM, Richard Damon wrote:
>>> On 4/23/25 11:22 PM, polcott333 wrote:
>>>> On 4/23/2025 9:41 PM, Richard Damon wrote:
>>>>> On 4/23/25 11:32 AM, olcott wrote:
>>>>>> On 4/23/2025 6:25 AM, joes wrote:
>>>>>>> Am Tue, 22 Apr 2025 13:51:48 -0500 schrieb olcott:
>>>>>>>> On 4/22/2025 1:07 PM, Fred. Zwarts wrote:
>>>>>>>>> Op 22.apr.2025 om 18:28 schreef olcott:
>>>>>>>>>> On 4/22/2025 7:57 AM, joes wrote:
>>>>>>>>>>> Am Tue, 15 Apr 2025 15:44:06 -0500 schrieb olcott:
>>>>>>>
>>>>>>>>>>>> You continue to stupidly insist that int sum(int x, int y) 
>>>>>>>>>>>> {return x
>>>>>>>>>>>> + y; }
>>>>>>>>>>>> returns 7 for sum(3,2) because you incorrectly understand 
>>>>>>>>>>>> how these
>>>>>>>>>>>> things fundamentally work.
>>>>>>>>>>>>
>>>>>>>>>>>> It is stupidly wrong to expect HHH(DD) report on the direct
>>>>>>>>>>>> execution of DD when you are not telling it one damn thing 
>>>>>>>>>>>> about
>>>>>>>>>>>> this direct execution.
>>>>>>>>>>> What else is it missing that the processor uses to execute it?
>>>>>>>>>>>
>>>>>>>>>> libx86emu <is> a correct x86 processor and does emulate its 
>>>>>>>>>> inputs
>>>>>>>>>> correctly.
>>>>>>>>>
>>>>>>>>> The key thing here is that Olcott consistently does not 
>>>>>>>>> understand that
>>>>>>>>> HHH is given a finite string input that according to the 
>>>>>>>>> semantics of
>>>>>>>>> the x86 language specifies a halting program,
>>>>>>>>
>>>>>>>> That is stupidly incorrect.
>>>>>>> No, DD halts (when executed directly). HHH is not a halt decider, 
>>>>>>> not even
>>>>>>> for DD only.
>>>>>>>
>>>>>>>> People here stupidly assume that the outputs are not required to
>>>>>>>> correspond to the inputs.
>>>>>>> But the direct execution of DD is computable from its description.
>>>>>>>
>>>>>>
>>>>>> Not as an input to HHH.
>>>>>
>>>>> But neither the "direct execution" or the "simulation by HHH" are 
>>>>> "inputs" to HHH. What is the input is the representation of the 
>>>>> program to be decided on.
>>>>>
>>>>>> When HHH computes halting for DD is is only allowed
>>>>>> to apply the finite string transformations specified
>>>>>> by the x86 language to the machine code of DD.
>>>>>
>>>>> It is only ABLE to apply them.
>>>>>
>>>>
>>>> The input to HHH(DD) does specify the recursive emulation
>>>> of DD including HHH emulating itself emulating DD when
>>>> one applies the finite string transformation rules of the
>>>> x86 language to THE INPUT to HHH(DD).
>>>
>>> Yes, the input specifies FINITE recusive PARTIAL emulation, as the 
>>> HHH that DD calls will emulate only a few instructions of DD and then 
>>> return,
>>>
>>
>> *You are technically incompetent on this point*
>> When the finite string transformation rules of the
>> x86 language are applied to the input to HHH(DD)
>> THIS DD CANNOT POSSIBLY REACH ITS FINAL HALT STATE
>> not even after an infinite number of emulated steps.
> 
> Sure it does, just after the point that HHH gives up on those 
> transformation and aborts its (now incorrect) emulation of the input.
> 

THAT IS COUNTER FACTUAL !!!

The directly executed DD has zero recursive invocations.
DD emulated by HHH has one recursive invocation.

Did you know that zero does not equal one?

-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer