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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory
Subject: Re: Halting Problem: What Constitutes Pathological Input
Date: Wed, 7 May 2025 13:04:33 +0200
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Op 06.mei.2025 om 22:49 schreef olcott:
> On 5/6/2025 3:42 PM, dbush wrote:
>> On 5/6/2025 4:33 PM, olcott wrote:
>>> On 5/6/2025 2:38 PM, dbush wrote:
>>>> On 5/6/2025 2:55 PM, olcott wrote:
>>>>> On 5/6/2025 7:12 AM, dbush wrote:
>>>>>> On 5/6/2025 12:55 AM, olcott wrote:
>>>>>>> On 5/5/2025 3:53 PM, Richard Heathfield wrote:
>>>>>>>> On 05/05/2025 20:38, olcott wrote:
>>>>>>>>> On 5/5/2025 2:23 PM, Richard Heathfield wrote:
>>>>>>>>>> On 05/05/2025 20:20, olcott wrote:
>>>>>>>>>>> Is "halts" the correct answer for H to return?  NO
>>>>>>>>>>> Is "does not halt" the correct answer for H to return?  NO
>>>>>>>>>>> Both Boolean return values are the wrong answer
>>>>>>>>>>
>>>>>>>>>> Or to put it another way, the answer is undecidable, QED.
>>>>>>>>>>
>>>>>>>>>> See? You got there in the end.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> Is this sentence true or false: "What time is it?"
>>>>>>>>
>>>>>>>> 20:45GMT, give or take.
>>>>>>>>
>>>>>>>>> is also "undecidable" because it is not a proposition
>>>>>>>>> having a truth value.
>>>>>>>>
>>>>>>>> No, it's computable and therefore decidable. Your computer is 
>>>>>>>> perfectly capable of displaying its interpretation of the time.
>>>>>>>>
>>>>>>>>> Is this sentence true or false: "This sentence is untrue."
>>>>>>>>> is also "undecidable" because it is not a semantically sound
>>>>>>>>> proposition having a truth value.
>>>>>>>>
>>>>>>>> But we know that it halts at the full stop.
>>>>>>>>
>>>>>>>>> Can Carol correctly answer “no” to this (yes/no) question?
>>>>>>>>
>>>>>>>> You have, I see, learned that not all yes/no questions are 
>>>>>>>> decidable. Well done! You're coming along nicely.
>>>>>>>>
>>>>>>>>> Both Yes and No are the wrong answer proving that
>>>>>>>>> the question is incorrect when the context of who
>>>>>>>>> is asked is understood to be a linguistically required
>>>>>>>>> aspect of the full meaning of the question.
>>>>>>>>
>>>>>>>> The question is grammatically and syntactically unremarkable. I 
>>>>>>>> see no grounds for claiming that it's 'incorrect'. It's just 
>>>>>>>> undecidable.
>>>>>>>>
>>>>>>>> You appear to be trying to overturn the Halting Problem by 
>>>>>>>> claiming that Turing somehow cheated. You're entitled to hold 
>>>>>>>> that opinion, but it's not one that will gain any traction with 
>>>>>>>> peer reviewers when you try to publish.
>>>>>>>>
>>>>>>>
>>>>>>> *EVERYONE IGNORES THIS*
>>>>>>> It is very simple the mapping from inputs to outputs
>>>>>>> must have a well defined sequence of steps.
>>>>>>>
>>>>>>
>>>>>> FALSE!!!
>>>>>>
>>>>>> There is no requirement that mappings have steps to compute them.
>>>>>>
>>>>>
>>>>> The requirement is that 
>>>>
>>>> Assuming that an algorithm exists that can compute the following 
>>>> mapping:
>>>>
>>>>
>>>> Given any algorithm (i.e. a fixed immutable sequence of 
>>>> instructions) X described as <X> with input Y:
>>>>
>>>> A solution to the halting problem is an algorithm H that computes 
>>>> the following mapping:
>>>>
>>>> (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
>>>> (<X>,Y) maps to 0 if and only if X(Y) does not halt when executed 
>>>> directly
>>>>
>>>>
>>>>> OUTPUTS must correspond
>>>>> to INPUTS. This requires that outputs must be
>>>>> derived from INPUTS.
>>>>
>>>> And when a contradiction is reached that proves the above assumption 
>>>> false, as Linz and others have proved, and you have *explicitly* 
>>>> admitted is correct.
>>>
>>> As I already said Linz is only correct when the halting
>>> problem proof is construed as 
>>
>> After assuming that an algorithm exists to map the halting function
>>
>>> having an input that can
>>> actually do the opposite of whatever value the termination
>>> analyzer returns. Since this is false,
>>
>> That proves the above assumption false, as Linz and others have proved 
>> and as you have *explicitly* agreed is correct.
>>
> 
> The fundamental basic assumption of all of the halting
> problem proofs is that an input can actually do the
> opposite of whatever value its decider returns.
> THIS ASSUMPTION IS FALSE.
> THE "DOING THE OPPOSITE" CODE IS UNREACHABLE.
> 


The code is not unreachable, but the programmer decided to add code to 
abort before it could reach it. That error does not change the behaviour 
of the program specified in the input.