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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Computing the mapping from the input to HHH(DD) --- REFUTES
INCORRECT REQUIREMENTS
Date: Fri, 9 May 2025 13:17:29 -0500
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On 5/9/2025 11:49 AM, Mike Terry wrote:
> On 09/05/2025 17:30, Richard Heathfield wrote:
>> On 09/05/2025 17:25, olcott wrote:
>>> void DDD()
>>> {
>>> HHH(DDD);
>>> return;
>>> }
>>>
>>> When 1 or more statements of DDD are correctly
>>> simulated by HHH then this correctly simulated
>>> DDD cannot possibly reach its own “return statement”.
>>> (final halt state)
>>
>> You beg the question.
>>
>> You have not shown that HHH correctly simulates anything.
>>
>> Mike Terry, on the other hand, has shown that it fails to correctly
>> simulate DDD.
>>
>
> It may correctly /partially/ simulate DDD, in the sense of correctly
> simulating the sequence of instructions of DDD until it decides to stop
> simulating. Well, in practice there is the complication that PO's code
> has design bugs meaning that what PO calls a simulation is NOT actually
> valid, due to misuse of global variables in his code! To be valid, the
> sequence of instructions simulated must match the instructions of the
> computation being simulated (i.e. match the instruction sequence of the
> independently executed computation.
>
> Obviously a partial simulation (even a valid one) not reaching the halt
> state does not mean that the computation being simulated never halts.
>
>
> Mike.
void DDD()
{
HHH(DDD);
return;
}
When 1 or more statements of DDD are correctly
simulated by HHH then this correctly simulated
DDD cannot possibly reach its own “return statement”.
That a correctly simulated input cannot possibly
reach its own simulated final halt state proves
that this simulated input cannot possibly halt.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer