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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory
Subject: Re: Incorrect requirements --- Computing the mapping from the input
 to HHH(DD)
Date: Sat, 10 May 2025 10:52:51 +0200
Organization: A noiseless patient Spider
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Op 09.mei.2025 om 17:59 schreef olcott:
> On 5/9/2025 4:00 AM, Fred. Zwarts wrote:
>> Op 09.mei.2025 om 02:05 schreef olcott:
>>> On 5/8/2025 6:54 PM, Keith Thompson wrote:
>>>> olcott <polcott333@gmail.com> writes:
>>>>> On 5/8/2025 6:30 PM, Richard Heathfield wrote:
>>>>>> On 08/05/2025 23:50, olcott wrote:
>>>> [...]
>>>>>>> If you are a competent C programmer
>>>>>> Keith Thompson is a highly-respected and very competent C
>>>>>> programmer.
>>>>>
>>>>> *Then he is just who I need*
>>>>
>>>> No, what you need is someone who is an expert in mathematical logic
>>>> (I am not) who can explain to you, in terms you can understand and
>>>> accept, where you've gone wrong.  Some expertise in C could also
>>>> be helpful.
>>>>
>>>
>>> The key gap in my proof is that none of the comp.sci
>>> people seems to have a slight clue about simple C
>>> programming.
>>>
>>> void DDD()
>>> {
>>>    HHH(DDD);
>>>    return;
>>> }
>>>
>>> *THIS IS THE C PART THAT NO ONE HERE UNDERSTANDS*
>>> DDD correctly simulated by HHH cannot possibly
>>> reach its own "return" instruction.
>>
>> The HHH that you propose and is included in DDD does halt. But it is 
>> known that this HHH prematurely aborts which makes it impossible for 
>> the simulation to reach the reachable 'return'. HHH simply ignores the 
>> conditional abort in the simulation.
>>
> 
> void DDD()
> {
>    HHH(DDD);
>    return;
> }
> 
> When 1 or more statements of DDD are correctly
> simulated by HHH then this correctly simulated
> DDD cannot possibly reach its own “return statement”.
> 
No need to repeat this failure of HHH to reach the end of a halting 
program again and again.