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Path: ...!weretis.net!feeder9.news.weretis.net!news.quux.org!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: dbush <dbush.mobile@gmail.com> Newsgroups: comp.theory Subject: Re: Incorrect requirements --- Computing the mapping from the input to HHH(DD) Date: Sun, 11 May 2025 16:21:13 -0400 Organization: A noiseless patient Spider Lines: 234 Message-ID: <vvr0ro$k1ua$1@dont-email.me> References: <vv97ft$3fg66$1@dont-email.me> <vvo58a$3lnkd$1@dont-email.me> <dc76ef3215a83481dfddc40c466bb9ebc0e77341.camel@gmail.com> <vvo709$3m1oc$1@dont-email.me> <b503e969e23dd1b2a6201ba78c82c9ff7906eaae.camel@gmail.com> <vvo9e8$3m1oc$3@dont-email.me> <b9cec56c1d257e09fdf8043f02f123a4243de6e1.camel@gmail.com> <vvoife$3ofmu$1@dont-email.me> <09cea75db07408dc9203aca3fb74408ad3a095b4.camel@gmail.com> <vvoubl$3qtsi$1@dont-email.me> <bc4fb153ff914177dba706ce6e0dfb467e2126eb.camel@gmail.com> <vvp04i$3r5li$3@dont-email.me> <853816e160c7b3fe75c71f0728e72989d9fb2e41.camel@gmail.com> <vvp1fm$3r5li$4@dont-email.me> <b049926b61baa5d69d11655a8af06e537b7acd71.camel@gmail.com> <vvqga9$gldn$3@dont-email.me> <41e08841caf0d628beb5105bc78531a412eea440.camel@gmail.com> <vvql3p$gldn$15@dont-email.me> <cb999b6746607a1445c196e485a2c1124eaee8b5.camel@gmail.com> <vvqnev$i5d0$3@dont-email.me> <07c4f2302645a7e58957b5e5bffed80397a6ddae.camel@gmail.com> <vvr0ot$k9nu$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Sun, 11 May 2025 22:21:13 +0200 (CEST) Injection-Info: dont-email.me; posting-host="aad4969e8ca95f1c06ff9de97da90e9e"; logging-data="657354"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18r+5Lt9QGELCxx0TQX3CNR" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:favgX35pfUjjcFbiwNr0nYLXlTM= Content-Language: en-US In-Reply-To: <vvr0ot$k9nu$1@dont-email.me> Bytes: 10999 On 5/11/2025 4:19 PM, olcott wrote: > On 5/11/2025 1:38 PM, wij wrote: >> On Sun, 2025-05-11 at 12:40 -0500, olcott wrote: >>> On 5/11/2025 12:21 PM, wij wrote: >>>> On Sun, 2025-05-11 at 12:00 -0500, olcott wrote: >>>>> On 5/11/2025 11:28 AM, wij wrote: >>>>>> On Sun, 2025-05-11 at 10:38 -0500, olcott wrote: >>>>>>> On 5/11/2025 9:34 AM, wij wrote: >>>>>>>> On Sat, 2025-05-10 at 21:19 -0500, olcott wrote: >>>>>>>>> On 5/10/2025 9:09 PM, wij wrote: >>>>>>>>>> On Sat, 2025-05-10 at 20:56 -0500, olcott wrote: >>>>>>>>>>> On 5/10/2025 8:44 PM, wij wrote: >>>>>>>>>>>> On Sat, 2025-05-10 at 20:26 -0500, olcott wrote: >>>>>>>>>>>>> On 5/10/2025 8:17 PM, wij wrote: >>>>>>>>>>>>>> On Sat, 2025-05-10 at 17:03 -0500, olcott wrote: >>>>>>>>>>>>>>> On 5/10/2025 4:44 PM, wij wrote: >>>>>>>>>>>>>>>> On Sat, 2025-05-10 at 14:29 -0500, olcott wrote: >>>>>>>>>>>>>>>>> On 5/10/2025 2:02 PM, wij wrote: >>>>>>>>>>>>> >>>>>>>>>>>>>> >>>>>>>>>>>>>> You don't know the counter example in the HP proof, your D >>>>>>>>>>>>>> is not the case >>>>>>>>>>>>>> what HP >>>>>>>>>>>>>> says. >>>>>>>>>>>>>> >>>>>>>>>>>>> >>>>>>>>>>>>> Sure I do this is it! (as correctly encoded in C) >>>>>>>>>>>>> >>>>>>>>>>>>> typedef void (*ptr)(); >>>>>>>>>>>>> int HHH(ptr P); >>>>>>>>>>>>> >>>>>>>>>>>>> int DD() >>>>>>>>>>>>> { >>>>>>>>>>>>> int Halt_Status = HHH(DD); >>>>>>>>>>>>> if (Halt_Status) >>>>>>>>>>>>> HERE: goto HERE; >>>>>>>>>>>>> return Halt_Status; >>>>>>>>>>>>> } >>>>>>>>>>>>> >>>>>>>>>>>>> int main() >>>>>>>>>>>>> { >>>>>>>>>>>>> HHH(DD); >>>>>>>>>>>>> } >>>>>>>>>>>>> >>>>>>>>>>>>> >>>>>>>>>>>> >>>>>>>>>>>> Try to convert it to TM language to know you know nothing. >>>>>>>>>>>> >>>>>>>>>>> >>>>>>>>>>> I spent 22 years on this. I started with the Linz text >>>>>>>>>>> >>>>>>>>>>> When Ĥ is applied to ⟨Ĥ⟩ >>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>>>>>> or >>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>>>>> >>>>>>>>>>> (a) Ĥ copies its input ⟨Ĥ⟩ >>>>>>>>>>> (b) Ĥ invokes embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ >>>>>>>>>>> (c) embedded_H simulates ⟨Ĥ⟩ ⟨Ĥ⟩ ... >>>>>>>>>>> >>>>>>>>>>> Thus ⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by embedded_H >>>>>>>>>>> cannot possibly reach its simulated final halt state >>>>>>>>>>> ⟨Ĥ.qn⟩ >>>>>>>>>>> >>>>>>>>>>>> To refute the HP, you need to understand what it exactly >>>>>>>>>>>> means in TM. >>>>>>>>>>> >>>>>>>>>>> I have known this for 22 years. >>>>>>>>>> >>>>>>>>>> A working TM. Build it explicitly from transition function, >>>>>>>>>> then explain >>>>>>>>>> your derivation. You know nothing. >>>>>>>>>> >>>>>>>>> >>>>>>>>> That would be like examining how an operating system >>>>>>>>> works entirely from its machine code. >>>>>>>> >>>>>>>> You are refuting a CS foundamental theorem (i.e. HP) officially. >>>>>>>> So, yes, and actually MORE need to be done (beyond your >>>>>>>> imagination). >>>>>>>> >>>>>>>> Knowing a car or smart phone,... is far different from making one. >>>>>>>> Knowing E=mc^2 is far from knowing relativity, making A-bomb >>>>>>>> (actually, making >>>>>>>> A-bomb don't need to know E=mc^2, people are often fooled by >>>>>>>> popular saying) >>>>>>>> Every chapter of Linz's book, C text textbook has exercises, you >>>>>>>> need to those >>>>>>>> exercises AT LEAST to comment CS (and computation theory is more >>>>>>>> advanced topic >>>>>>>> than TM). Saying so is because we know you can't do the exercise >>>>>>>> and boast lots >>>>>>>> about TM stuff (and pretty much anything else from just reading >>>>>>>> words), even >>>>>>>> about theorem. >>>>>>>> >>>>>>> >>>>>>> When Ĥ is applied to ⟨Ĥ⟩ >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>> or >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> >>>>>>> (a) Ĥ copies its input ⟨Ĥ⟩ >>>>>>> (b) Ĥ invokes embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ >>>>>>> (c) embedded_H simulates ⟨Ĥ⟩ ⟨Ĥ⟩ >>>>>>> >>>>>>> All that I need to know is that I proved that >>>>>>> embedded_H correctly recognizes the repeating >>>>>>> pattern where its correctly simulated ⟨Ĥ⟩ ⟨Ĥ⟩ >>>>>>> cannot possibly reach its own simulated final >>>>>>> halt state of ⟨Ĥ.qn⟩ >>>>>>> >>>>>>> https://www.liarparadox.org/Linz_Proof.pdf >>>>>>> >>>>>>>>> We only have to actually know one detail: >>>>>>>>> Every counter-example input encoded in any model >>>>>>>>> of computation always specifies recursive simulation >>>>>>>>> that never halts to its corresponding simulating >>>>>>>>> termination analyzer. >>>>>>>> >>>>>>>> More example here that you don't understand nearly all CS terms. >>>>>>>> >>>>>>> >>>>>>> Mere empty rhetoric entirely bereft of any supporting >>>>>>> reasoning. The x86 language is comparable to a RASP >>>>>>> machine that is equivalent to a Turing machine. >>>>>> >>>>>> Question: >>>>>> 1. Do you understand that you can't do the exercises in Linz's book? >>>>> >>>>> Everything is 100% irrelevant besides the fact that >>>>> I have shown that ⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by >>>>> embedded_H cannot possibly reach its own simulated >>>>> final halt state ⟨Ĥ.qn⟩. Thus when embedded_H reports >>>>> on the behavior that its input specifies it can >>>>> correctly transition to Ĥ.qn. >>>>> >>>>>> 2. Do you understand your ability of C/assembly/TM is less than 1 >>>>>> year CS level? >>>>>> >>>>> >>>>> I construe C as high level assembly language thus >>>>> disregard any inessentials. No change since K & R >>>>> is of any use to me. I write C++ the same way. I >>>>> use it as C with classes. I also use std::vector a lot. >>>> >>>> Q3. If people know the capability of the author of POOH is less than >>>> 1 year CS >>>> level. How persuasive and reliable of POOH do you think it >>>> would be? >>>> >>>> Q4: Why no one can reproduce the result of POOH for these 22? years? >>>> >>>> >>> >>> _DDD() >>> [00002172] 55 push ebp ; housekeeping >>> [00002173] 8bec mov ebp,esp ; housekeeping ========== REMAINDER OF ARTICLE TRUNCATED ==========