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Le 16/08/2024 à 19:39, Jim Burns a écrit :

> no element of ℕᵈᵉᶠ is its upper.end,
> because
> for each diminishable k
> diminishable k+1 disproves by counter.example
> that k is the upper.end of ℕᵈᵉᶠ

SBZ(x) starts with 0 at 0 and increases, but at no point x it increases by 
more than 1 because of
∀n ∈ ℕ: 1/n - 1/(n+1) > 0. 
Therefore there is a smallest unit fractions and vice versa a greatest 
natnumber.
What can't you understand?

Regards, WM