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X-Received: by 2002:a05:620a:1e4:b0:74d:dcc:c9be with SMTP id x4-20020a05620a01e400b0074d0dccc9bemr718977qkn.0.1681661727682; Sun, 16 Apr 2023 09:15:27 -0700 (PDT) X-Received: by 2002:a25:e00c:0:b0:b8f:cef7:368d with SMTP id x12-20020a25e00c000000b00b8fcef7368dmr5024294ybg.1.1681661727400; Sun, 16 Apr 2023 09:15:27 -0700 (PDT) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Sun, 16 Apr 2023 09:15:27 -0700 (PDT) In-Reply-To: <O66hF0j_92-obntg6lU7fYtWTMA@jntp> Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:5de:b408:7208:abc9; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:5de:b408:7208:abc9 References: <u0r2k6$161g2$1@dont-email.me> <u13que$2kt04$1@dont-email.me> <u13t5s$rq$2@shakotay.alphanet.ch> <u13u8n$2l71c$2@dont-email.me> <eu6-atxrEppmGwQfAd86ghgZ6-U@jntp> <u1434c$2m51m$2@dont-email.me> <T66X88xOsCfsVOT48hqiAurwkDY@jntp> <fe9be762-f1d1-4c40-b169-a6c969839efcn@googlegroups.com> <YqbmW7-BFyfzFdxsU3tGoIHAgXM@jntp> <u1f70i$26j1b$1@dont-email.me> <O66hF0j_92-obntg6lU7fYtWTMA@jntp> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <08d2771b-4384-4e19-9a33-70dcf9f0da20n@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_Quand_l=27I=2EA=2E_p=C3=A8te_les_plombs_sur_la_RR=2E?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Sun, 16 Apr 2023 16:15:27 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2745 Lines: 21 > > Qu'est-ce que c'est que cette nouvelle sottise, Jacques ? La rapidit=C3= =A9=20 > > n'est pas argsh(v/c) mais artanh(v/c) ! Et l=C3=A0, oui, on tombe sur= =20 > > additivit=C3=A9. Avec argsh =C3=A7a ne marche pas. De plus en plus s=C3= =A9nile le=20 > > Jacques. > Exact, Argth(v/c). Etourderie dans la notation. _______________ Vous avez tous les deux raisons. J=E2=80=99ai pas mal travaill=C3=A9 sur ce probl=C3=A8me de relativit=C3=A9= .. J=E2=80=99en suis arriv=C3=A9 =C3=A0 la conclusion qu=E2=80=99il y avait = deux r=C3=A9alit=C3=A9s, d=E2=80=99un c=C3=B4t=C3=A9 ce que nous percevons,= la r=C3=A9alit=C3=A9 perceptible, et de l=E2=80=99autre la vraie r=C3=A9al= it=C3=A9, le r=C3=A9el, ce qui fait qu=E2=80=99il y a deux vitesses, une vi= tesse per=C3=A7ue, mesur=C3=A9e, u (inf=C3=A9rieure =C3=A0 c) et une vitess= e r=C3=A9elle v telles que v =3D u/=CE=B3 (=CE=B3 =C3=A9tant le coefficient= de Lorentz).=20 D=C3=A8s lors la rapidit=C3=A9 s=E2=80=99=C3=A9crit: r =3D artanh (u/c) =3D= arsinh (v/c). Oui, je sais, =C3=A7a surprend un peu, mais, moi aussi, =C3=A7a m=E2=80=99a= =C3=A9tonn=C3=A9.