X-Received: by 2002:a05:6214:27c4:b0:472:6d89:a12 with SMTP id ge4-20020a05621427c400b004726d890a12mr24641256qvb.7.1656876928593;
        Sun, 03 Jul 2022 12:35:28 -0700 (PDT)
X-Received: by 2002:a25:da15:0:b0:66e:189f:8e77 with SMTP id
 n21-20020a25da15000000b0066e189f8e77mr11160842ybf.370.1656876928347; Sun, 03
 Jul 2022 12:35:28 -0700 (PDT)
Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail
Newsgroups: fr.rec.philatelie
Date: Sun, 3 Jul 2022 12:35:28 -0700 (PDT)
Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e0a:b02:2a20:6900:648a:1017:9aeb;
 posting-account=M0mjGwoAAABcK3YycRBTLWGLLq_DTGuh
NNTP-Posting-Host: 2a01:e0a:b02:2a20:6900:648a:1017:9aeb
User-Agent: G2/1.0
MIME-Version: 1.0
Message-ID: <364ce573-671d-405c-b4d6-c46fca7b539en@googlegroups.com>
Subject: =?UTF-8?Q?Lettre_tax=C3=A9e_en_2022?=
From: =?UTF-8?Q?Beno=C3=AEt_Lebourcq?= <benoit.lebourcq@gmail.com>
Injection-Date: Sun, 03 Jul 2022 19:35:28 +0000
Content-Type: text/plain; charset="UTF-8"
Content-Transfer-Encoding: quoted-printable
Bytes: 1761
Lines: 18

Bonjour,

J'ai re=C3=A7u derni=C3=A8rement une lettre tax=C3=A9e.
Le montant =C3=A0 payer est de 4.00 =E2=82=AC (taxe de traitement de 2.86 =
=E2=82=AC plus affranchissement manquant =C3=A0 1.14 =E2=82=AC).

Depuis le 1er janvier 2020, les C.G.V. (art. 4.7.2), il semble que les lett=
res insuffisamment affranchies doivent =C3=AAtre tax=C3=A9es du montant man=
quant major=C3=A9 de 10% maximum. L'ancien calcul en vigueur depuis 1980 a =
=C3=A9t=C3=A9 utilis=C3=A9.

Voir l'image ci-dessous :

https://zupimages.net/viewer.php?id=3D22/26/fyb3.jpg

Merci de votre opinion.

Beno=C3=AEt.