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Date: Fri, 18 Aug 2023 11:23:34 -0700 (PDT)
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Subject: Re: Transformations relativistes circulaires
From: Richard Verret <rverret97@gmail.com>
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Le vendredi 18 ao=C3=BBt 2023 =C3=A0 18:52:26 UTC+2, Richard Hachel a =C3=
=A9crit=C2=A0:
> Le 18/08/2023 =C3=A0 18:30, Richard Verret a =C3=A9crit :=20
> > Ce qui fait qu=E2=80=99on retrouve l=E2=80=99addition des vitesses de l=
a relativit=C3=A9, avec=20
> > les vitesses perceptibles, il suffit de calculer sh y2 on obtient v2 =
=3D... mais je=20
> > vous laisse faire le calcul.
> Tu as fait les calculs en prenant la base des vitesses r=C3=A9elles?=20

Les formules d=E2=80=99addition des vitesses r=C3=A9elles et apparentes s=
=E2=80=99obtiennent ainsi:
on a y2 =3D y1 + y2/1 d=E2=80=99o=C3=B9=20
sh y2 =3D sh (y1 + y2/1) =3D sh y1 * ch y2/1 + ch y1 sh y2/1 et
th y2 =3D (th y1 + th y2/1)/(1 + th y1 * th y2/1).
Comme y =3D arsh v/c =3D arth Vp/c, on trouve ais=C3=A9ment les formules.
Pour les vitesses apparentes on obtient:
th arth Vp,2 =3D Vp,2 =3D (Vp,1 + Vp,2/1)/(1 + Vp,1*Vp,2/1)