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X-Received: by 2002:ac8:75c8:0:b0:417:b53e:c659 with SMTP id z8-20020ac875c8000000b00417b53ec659mr224684qtq.13.1700564593253; Tue, 21 Nov 2023 03:03:13 -0800 (PST) X-Received: by 2002:a17:90a:8982:b0:280:a5e9:3b61 with SMTP id v2-20020a17090a898200b00280a5e93b61mr2492313pjn.9.1700564592893; Tue, 21 Nov 2023 03:03:12 -0800 (PST) Path: ...!weretis.net!feeder6.news.weretis.net!usenet.blueworldhosting.com!diablo1.usenet.blueworldhosting.com!peer03.iad!feed-me.highwinds-media.com!news.highwinds-media.com!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Tue, 21 Nov 2023 03:03:12 -0800 (PST) In-Reply-To: <040d417e-1a6a-4d9f-a118-0234d9f25b31n@googlegroups.com> Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e0a:170:e3f0:7c90:3b9a:d9c3:a31c; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2a01:e0a:170:e3f0:7c90:3b9a:d9c3:a31c References: <4c889034-b408-4498-a880-a388fdc24aa8n@googlegroups.com> <7b21a5dd-a52c-477d-8bdb-be6e5260e267n@googlegroups.com> <_6ou4b8bmlrDAYETF1jbHlXiAHs@jntp> <040d417e-1a6a-4d9f-a118-0234d9f25b31n@googlegroups.com> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <41d495eb-2174-43d1-9808-2282d60b2f4bn@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_=5BRR=5D_=5BRG=5D_Est=2Dil_possible_en_relativit=C3=A9_d=27avoir?= =?UTF-8?Q?_une_acc=C3=A9l=C3=A9ration_qui_ne_soit_pas_la_d=C3=A9riv=C3=A9e_d=27une_vites?= =?UTF-8?Q?se=2E?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Tue, 21 Nov 2023 11:03:13 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Received-Bytes: 2001 Bytes: 2234 Lines: 7 Le 21/11/2023 =C3=A0 11:25, Julien Arlandis a =C3=A9crit : > Au passage on prouve la coh=C3=A9rence de la formule v(t) contest=C3=A9e = par Richard, =C3=A0 savoir : > v(t) =3D a.t/sqrt(1+(a.t)^2/c^2) Il y a deux Richard. Quant =C3=A0 moi, je conteste cette approche, il est c= lair que la vitesse r=C3=A9elle v est =C3=A9gale =C3=A0 v =3D a.t puisque d= v/dt =3D a et que la vitesse perceptible/mesur=C3=A9e Vo =3D v/=CE=B3, on o= btient bien Vo =3D a t/=CE=B3.