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Subject: =?UTF-8?Q?Re=3A_De_la_relativit=C3=A9_des_distances?=
From: Richard Verret <rverret97@gmail.com>
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Bonjour M. Arlandis! La contraction des longueurs en relativit=C3=A9 donne =
L=E2=80=99 =3D k L avec k < 1; l=E2=80=99inverse du coefficient de Lorentz =
et non pas le coefficient lui-m=C3=AAme; k =3D sqrt(1 - (Vo/c)^2) https://f=
r.m.wikipedia.org/wiki/Contraction_des_longueurs La contraction des longueu=
rs dans la transformation r=C3=A9ciproque qui est =C3=A9galement la transfo=
rmation de Lorentz donne L =3D k L=E2=80=99 m=C3=AAme pour -v, d=E2=80=99o=
=C3=B9 L=3D k^2 L, relation qui n=E2=80=99est possible que si k =3D 1, or k=
 # 1  avec la transformation de Lorentz. Donc exit cette transformation.
Oui, je sais c=E2=80=99est tr=C3=A8s difficile d=E2=80=99admettre =C3=A7a p=
our les tenants de la relativit=C3=A9 qui ne jure que par la transformation=
 de Lorentz et cette stupidit=C3=A9 d=E2=80=99espace-temps.