Deutsch   English   Français   Italiano  
<5aba3db1-074b-4cf1-87a7-329a9bc5dfe3n@googlegroups.com>

View for Bookmarking (what is this?)
Look up another Usenet article

X-Received: by 2002:ac8:5c93:0:b0:3f3:90c4:79dc with SMTP id r19-20020ac85c93000000b003f390c479dcmr687937qta.11.1683540596768;
        Mon, 08 May 2023 03:09:56 -0700 (PDT)
X-Received: by 2002:a81:aa0a:0:b0:54c:2409:c306 with SMTP id
 i10-20020a81aa0a000000b0054c2409c306mr5680355ywh.6.1683540596092; Mon, 08 May
 2023 03:09:56 -0700 (PDT)
Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail
Newsgroups: fr.sci.physique
Date: Mon, 8 May 2023 03:09:55 -0700 (PDT)
In-Reply-To: <T66X88xOsCfsVOT48hqiAurwkDY@jntp>
Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:7d13:225e:5d4a:b936;
 posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi
NNTP-Posting-Host: 2001:861:8bb7:5500:7d13:225e:5d4a:b936
References: <u0r2k6$161g2$1@dont-email.me> <u13egk$2kc1l$1@dont-email.me>
 <u13jou$2ko1o$1@dont-email.me> <u13lqv$2l0ir$1@dont-email.me>
 <u13q9c$2l3vn$1@dont-email.me> <u13que$2kt04$1@dont-email.me>
 <u13t5s$rq$2@shakotay.alphanet.ch> <u13u8n$2l71c$2@dont-email.me>
 <eu6-atxrEppmGwQfAd86ghgZ6-U@jntp> <u1434c$2m51m$2@dont-email.me> <T66X88xOsCfsVOT48hqiAurwkDY@jntp>
User-Agent: G2/1.0
MIME-Version: 1.0
Message-ID: <5aba3db1-074b-4cf1-87a7-329a9bc5dfe3n@googlegroups.com>
Subject: =?UTF-8?Q?Re=3A_Quand_l=27I=2EA=2E_p=C3=A8te_les_plombs_sur_la_RR=2E?=
From: Richard Verret <rverret97@gmail.com>
Injection-Date: Mon, 08 May 2023 10:09:56 +0000
Content-Type: text/plain; charset="UTF-8"
Content-Transfer-Encoding: quoted-printable
Bytes: 2756
Lines: 19

Bonjour =C3=A0 tous-se! J=E2=80=99ai dit ailleurs que mon machin n=E2=80=99=
est pas en opposition avec la th=C3=A9orie de la relativit=C3=A9, je vais l=
e montrer sur un point en particulier.
J=E2=80=99ai postul=C3=A9 un espace g=C3=A9n=C3=A9ral G produit d=E2=80=99u=
n espace physique E par un espace des vitesses F, ce dernier =C3=A9tant tel=
 que=20
y =CE=B5 F, y =3D b f avec b =3D arsh v/c =3D arth Vo/c, v, la vitesse r=C3=
=A9elle v =C3=A9tant li=C3=A9e =C3=A0 la vitesse observ=C3=A9e Vo par le co=
efficient de Lorentz =CE=B3: v =3D =CE=B3 Vo.
La somme dans l=E2=80=99espace F de vitesses colin=C3=A9aires donne:
y =3D y1 + y2 tels que y =3D b f, y1 =3D b1 f, y2 =3D b2 f d=E2=80=99o=C3=
=B9 b =3D b1 + b2 soit:
arth Vo/c =3D arth Vo,1/c =3D arth Vo,2 d=E2=80=99o=C3=B9
th(arthVo/c) =3D (th( arthVo,1/c)+ th(arthVo,2/c))/ 1 + th(arthVo,1/c).th(a=
rthVo,2/c)
soit Vo =3D (Vo,1 + Vo,2)/1 + Vo,1 . Vo,2/c^2
qui est la formule d=E2=80=99addition des vitesses en relativit=C3=A9, http=
s://fr.m.wikiversity.org/wiki/Relativit=C3=A9_restreinte/Composition_des_vi=
tesses ,=20
alors voyez comme mon truc est en ad=C3=A9quation avec cette th=C3=A9orie!