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<64a7a468$0$24797$426a74cc@news.free.fr> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!2.eu.feeder.erje.net!feeder.erje.net!feeder1-2.proxad.net!proxad.net!feeder1-1.proxad.net!cleanfeed3-b.proxad.net!nnrp5-1.free.fr!not-for-mail Date: Fri, 7 Jul 2023 07:36:39 +0200 MIME-Version: 1.0 User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:102.0) Gecko/20100101 Thunderbird/102.11.0 Subject: =?UTF-8?Q?Re=3a_Neuf_possibilit=c3=a9s?= Newsgroups: fr.sci.maths References: <YEKqct9Ik97GKR6YVohuiDjUVKo@jntp> <64a73d51$0$31522$426a74cc@news.free.fr> Content-Language: fr From: Michel Talon <talon@niobe.lpthe.jussieu.fr> In-Reply-To: <64a73d51$0$31522$426a74cc@news.free.fr> Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Lines: 11 Message-ID: <64a7a468$0$24797$426a74cc@news.free.fr> Organization: Guest of ProXad - France NNTP-Posting-Date: 07 Jul 2023 07:36:40 CEST NNTP-Posting-Host: 88.161.173.7 X-Trace: 1688708200 news-3.free.fr 24797 88.161.173.7:16856 X-Complaints-To: abuse@proxad.net Bytes: 1262 Le 07/07/2023 à 00:16, Michel Talon a écrit : > Reste à prouver > qu'il n'y a pas d'autre solution. Si x <= y <= z et x >= 5 alors 1/x, 1/y et 1/z sont <= 1/5 et donc leur somme <=3/5 ne peut être égale à 1. -- Michel Talon