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Subject: Re: \advance\toks 41{...}
From: Florent CHERVET <florestan.chervet@gmail.com>
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Le samedi 14 octobre 2023 =C3=A0 19:27:28 UTC+2, Texboy a =C3=A9crit=C2=A0:
> Le 13/10/2023 =C3=A0 15:13, G=C3=A9rard Lemenn a =C3=A9crit :=20
>=20
> >> Pour =C3=AAtre plus pr=C3=A9cis :=20
> >> \toks 0=3D\toks 10=20
> >>=20
> >> est ultra rapide, car alors \toks 0 pointe sur la m=C3=AAme chaine que=
 \toks 10=20
> >> Il n'y a pas de copie du contenu de \toks 10 dans \toks 0.
> Ah ?=20
>=20
> \toks0=3D{A} \toks10=3D{B}=20
> \toks0=3D\toks10=20
> \toks10=3D{C}=20
> \showthe\toks0 % donne B et non pas C

Exactement :
1ere ligne : vous d=C3=A9finissez deux cha=C3=AEnes, ind=C3=A9pendamment
2=C3=A8 ligne : \toks 0 pointe vers la m=C3=AAme chaine que \toks 10
3=C3=A8 ligne : \toks 10 pointe vers la nouvelle cha=C3=AEne : "C"

C'est comme quand on fait \let\A =3D\B
On ne recopie pas le contenu de \B, on fait simplement pointer
\A vers la m=C3=AAme m=C3=A9moire que \B...

Bon weekend.