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Melmoth,
J'ai vu que la discussion partait aussi sur le groupe anglais...
Pour ma part, je pr=C3=A9f=C3=A8re pour l'instant rester ici. Cela donne vi=
e =C3=A0 ce groupe....et puis cela part vite en tous sens l=C3=A0-bas avec =
l'autre Zingbroc qui pollue tout...