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From: Alain Ketterlin <alain@universite-de-strasbourg.fr.invalid>
Newsgroups: fr.comp.lang.python
Subject: Re: Projet Python : importation d'un dossier csv sous forme de matrice
Date: Thu, 03 Feb 2022 19:45:59 +0100
Organization: =?utf-8?Q?Universit=C3=A9?= de Strasbourg
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mand1n3 <nospam_playfairalikecestatut@outlook.com.invalid> writes:

> 0.00055 0.00008 0.00035 0.00038 0.00048 0.00011 0.00005 0.00009 0.00031 0=
..00006
> 0 0.00014 0.00020 0.00006 0.00009 0.00048 0.00022 0.00007 0.00018 0.00026
> 0.00004 0.00009 0 0.00001 0.00003 0 ; 0.00085 0.00004 0.00007 0.00004 0.0=
0070
> 0.00002 0.00001 0 0.00001 0 0 0.00010 0.00008 0.00002 0.00012 0.00015 0.0=
0001
> 0.00022 0.00028 0.00005 0 0.00002 0 0 0 0 ; 0.00010 0.00004 0.00006 0.000=
10
> 0.00020 0.00002 0.00001 0 0.00004 0.00002 0 0.00018 0.00010 0.00002 0.000=
08
> 0.00011 0.00004 0.00003 0.00005 0.00003 0.00004 0.00020 0 0 0 0

C'est du csv inhabituel, et pour stocker une matrice 26x26 (et pas
25x25), =C3=A7a s'apparente =C3=A0 de l'autoflagellation. Essaie :

with open (.....) as f:
    m =3D [[float (w) for w in b.split()] for b in f.read().split(";")]

si le fichier n'est pas trop grand, et sinon

with open (.....) as f:
    m =3D [[]]
    for line in f:
        for f in line.split ():
            if f =3D=3D ";":
                m.append ([])
            else:
                m[-1].append (float (f))


(pas test=C3=A9).

-- Alain.