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From: Alain Ketterlin <alain@universite-de-strasbourg.fr.invalid>
Newsgroups: fr.comp.lang.python
Subject: Re: Mon code est lourd
Date: Fri, 06 May 2022 21:46:00 +0200
Organization: =?utf-8?Q?Universit=C3=A9?= de Strasbourg
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yves <yves@free.invalid> writes:

> Le Thu, 05 May 2022 22:26:20 +0200, Alain Ketterlin a =C3=A9crit:
>
>> (Au passage : pourquoi utiliser des cha=C3=AEnes de caract=C3=A8res pour=
 les mois
>> ?
>> Un entier serait plus simple =C3=A0 manipuler.)

> Pour ce qui est des cha=C3=AEnes de caract=C3=A8res, c'est surtout que j'=
ai =C3=A9pur=C3=A9=20
> au maximum mon expos=C3=A9 du probl=C3=A8me.

C'=C3=A9tait juste une remarque en passant.

> En r=C3=A9alit=C3=A9, ma source de donn=C3=A9e actuelle c'est plut=C3=B4t=
 ce code l=C3=A0:

> from datetime import datetime, timedelta, date
>
> def genereXdates2():
>     dateDepart  =3D "26012022"
>     dateFin =3D "07052022"
>     depart =3D datetime.strptime(dateDepart, '%d%m%Y')
>     fin =3D datetime.strptime(dateFin, '%d%m%Y')
>     date =3D depart
>     dict_transcodage =3D {"6": "S", "0": "D", "1":"L", "2":"M", "3":"M",=
=20
> "4":"J", "5":"V"}
>     while date !=3D fin:
>=20=20=20=20=20=20=20=20=20
>         yield(date.strftime("%m"),dict_transcodage[date.strftime('%w')],d=
ate.strftime('%d'))
>         date =3D date + timedelta(1)

Je proposais d'utiliser =C3=A0 la place :

        yield (date.month, "LMMJVSD"[date.weekday()], date.day)

(attention, weekday() ne suit pas la m=C3=AAme convention que "%w" pour str=
ftime).

C'est toi qui voit.

-- Alain.