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X-Received: by 2002:a05:6214:4a43:b0:56e:9ad3:ab9c with SMTP id ph3-20020a0562144a4300b0056e9ad3ab9cmr4496266qvb.1.1678293913531; Wed, 08 Mar 2023 08:45:13 -0800 (PST) X-Received: by 2002:ac8:102:0:b0:3b8:68fb:2b03 with SMTP id e2-20020ac80102000000b003b868fb2b03mr5318198qtg.7.1678293913340; Wed, 08 Mar 2023 08:45:13 -0800 (PST) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.electrotechnique Date: Wed, 8 Mar 2023 08:45:13 -0800 (PST) In-Reply-To: <63f9de8e$0$25937$426a74cc@news.free.fr> Injection-Info: google-groups.googlegroups.com; posting-host=2a01:e0a:275:6030:88c6:b7f6:9caf:fcd1; posting-account=Ad7QdAoAAADzsTYSINniVzR3yIbAp_kc NNTP-Posting-Host: 2a01:e0a:275:6030:88c6:b7f6:9caf:fcd1 References: <9e30d046-84d0-4ac6-b9f9-b2b70906b60fn@googlegroups.com> <63f73118$0$25941$426a74cc@news.free.fr> <fbad6481-ada9-49c8-a266-c77177ef51f4n@googlegroups.com> <63f9de8e$0$25937$426a74cc@news.free.fr> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <c4ab100f-6ff2-472c-a3f6-7b0c52e29bb5n@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_comment_d=C3=A9tecter_l=27origine_d=27un_courant_de_fuit?= =?UTF-8?Q?e?= From: jean-loup fabbro <jlfabbro@hotmail.com> Injection-Date: Wed, 08 Mar 2023 16:45:13 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2123 Lines: 17 Le samedi 25 f=C3=A9vrier 2023 =C3=A0 11:10:23 UTC+1, Olivier B. a =C3=A9cr= it=C2=A0: > jean-loup fabbro avait =C3=A9crit le 23/02/2023 :=20 > >=20 > > Oui merci bien, mais est-ce que vous savez comment trouver o=C3=B9 le f= il de=20 > > terre est rompu?=20 > > > Il faut en tester la continuit=C3=A9 avec une boucle que l'on tire =C3=A0= cot=C3=A9,=20 > en partant de la barrette de terre ou piquet pour remonter au fur et =C3= =A0=20 > mesure jusqu'au probl=C3=A8me.=20 >=20 > Mesures =C3=A0 faire disjoncteur de t=C3=AAte coup=C3=A9, =C3=A9videment. Bonsoir,=20 merci pour ce retour et d=C3=A9sol=C3=A9 du retard, je vais essayer. Cordialement.