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X-Received: by 2002:ad4:551d:0:b0:62f:ebba:b069 with SMTP id pz29-20020ad4551d000000b0062febbab069mr1865542qvb.9.1687343326728; Wed, 21 Jun 2023 03:28:46 -0700 (PDT) X-Received: by 2002:a25:e0c6:0:b0:bc7:f6af:8cff with SMTP id x189-20020a25e0c6000000b00bc7f6af8cffmr6237369ybg.2.1687343326409; Wed, 21 Jun 2023 03:28:46 -0700 (PDT) Path: ...!3.us.feeder.erje.net!1.us.feeder.erje.net!feeder.erje.net!usenet.blueworldhosting.com!diablo1.usenet.blueworldhosting.com!peer03.iad!feed-me.highwinds-media.com!news.highwinds-media.com!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Wed, 21 Jun 2023 03:28:46 -0700 (PDT) In-Reply-To: <qA6afYMjdkBHBa2CvvL2o5oyp7E@jntp> Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:80e8:aad2:824:3459; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:80e8:aad2:824:3459 References: <XsQK06WmG5UE8EA9eBhXPf3xb2A@jntp> <u5i5t3$3vbb3$10@dont-email.me> <36UjgdAhBfTjv9uuCKDaSCzXAmQ@jntp> <c44bec9e-04e0-4626-9eca-529542522240n@googlegroups.com> <bA2ekhxwlkk6fuDr9thgNgWZY54@jntp> <559d5430-f7e8-4f2a-84ed-f5fb91b64f7dn@googlegroups.com> <XzFAmPErLfSk_cqnrRguV4rk3g8@jntp> <8c3d183b-d91e-4c92-be6c-5438f5e3322fn@googlegroups.com> <-xhfl6BW3EgEvbi9Auk2vAySIJg@jntp> <a38573d3-ddf2-48fa-8b29-6f102f34bf86n@googlegroups.com> <qA6afYMjdkBHBa2CvvL2o5oyp7E@jntp> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <ce6c52a8-f947-49c6-bfb6-0f6ef54e3b1en@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_De_la_relativit=C3=A9_des_distances?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Wed, 21 Jun 2023 10:28:46 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Received-Bytes: 2401 Bytes: 2655 Lines: 12 Le mercredi 21 juin 2023 =C3=A0 11:59:29 UTC+2, Julien Arlandis a =C3=A9cri= t=C2=A0: > La transformation de Galil=C3=A9e serait donc simplement la matrice ident= it=C3=A9. Vous avez mal compris ou je n=E2=80=99ai pas =C3=A9t=C3=A9 assez clair. La= transformation de Galil=C3=A9e qui lie une figure F =C3=A0 une figure F=E2= =80=99 et donc un r=C3=A9f=C3=A9rentiel R a un autre r=C3=A9f=C3=A9rentiel = F=E2=80=99 en m.r.u. l=E2=80=99un par rapport =C3=A0 l=E2=80=99autre, suiva= nt l=E2=80=99axe des x, donne M=E2=80=99N=E2=80=99 =3D MN comme une transla= tion, par exemple, donne M=E2=80=99N=E2=80=99 =3D MN, d=E2=80=99o=C3=B9 l= =E2=80=99=C3=A9galit=C3=A9 des composantes de ces vecteurs x=E2=80=99 =3D x= , y=E2=80=99 =3D y, z=E2=80=99 =3D z.