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Path: ...!weretis.net!feeder8.news.weretis.net!pasdenom.info!from-devjntp Message-ID: <csJsb-exS9GBOplbZva05bW-CJY@jntp> JNTP-Route: news2.nemoweb.net JNTP-DataType: Article Subject: =?UTF-8?Q?=C3=A9quation=20?= Newsgroups: fr.sci.maths JNTP-HashClient: 2imp63GHTIB7K7eFBnu0qy3y1KE JNTP-ThreadID: ZD1uMbuXqUtSGEFBVD_-T6lcubo JNTP-Uri: http://news2.nemoweb.net/?DataID=csJsb-exS9GBOplbZva05bW-CJY@jntp User-Agent: Nemo/0.999a JNTP-OriginServer: news2.nemoweb.net Date: Mon, 04 Apr 22 12:48:13 +0000 Organization: Nemoweb JNTP-Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/100.0.4896.60 Safari/537.36 Injection-Info: news2.nemoweb.net; posting-host="b67bf6ef15ab89806174eb79fcba29ca7ef75505"; logging-data="2022-04-04T12:48:13Z/6771879"; posting-account="4@news2.nemoweb.net"; mail-complaints-to="newsmaster@news2.nemoweb.net" JNTP-ProtocolVersion: 0.21.1 JNTP-Server: PhpNemoServer/0.94.5 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-JNTP-JsonNewsGateway: 0.96 From: Richard Hachel <r.hachel@tiscali.fr> Bytes: 1480 Lines: 16 Bonjour les amis. Peut-on donner la réciproque de cette équation de façon simplifiée? t=(v/g)(1-v²/c²)^3/2 v= ? On peut commencer par passer g de l'autre côté. v.(1-v²/c²)^3/2 = gt Un mathématicien sait? R.H.