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From: Olivier Miakinen <om+news@miakinen.net>
Newsgroups: fr.sci.maths
Subject: =?UTF-8?Q?Re:_Pourquoi_le_r=c3=a9sultat_tend_toujours_vers_le_tripl?=
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Date: Tue, 25 Oct 2022 10:19:31 +0200
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Le 25/10/2022 03:24, "Benoît L." a écrit :
> Ni vu ni connu, le 24 octobre 2022 à 23:14, Olivier Miakinen osa
> écrire :
> 
> 
>> (x-z).100 - (x-z)
>> = (x-z).100 − 100 + 100 − (x-z)
>> = (x-z-1).100 + 90 + 10 − (x-z)
>> = (x-z-1).100 + 9.10 + (10-(x-z))
> 
> -100 + 100 = 90 + 10 ?

Non.  Le -100 sert à gauche, le +100 à droite :
1) (x-z).100 − 100 = (x-z-1).100
2) 100 = 90 + 10


-- 
Olivier Miakinen