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From: robby <moi@pla.net.invalid>
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Subject: =?UTF-8?Q?Re=3a_Petite_=c3=a9nigme_matricielle?=
Date: Mon, 24 Apr 2023 15:54:34 +0200
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On 19/04/2023 15:52, Julien Arlandis wrote:
> Il faut démontrer que (v * v_t)^n = (v * v_t) * 10^(2(n-1)) pour tout 
> entier n > 1,

en regardant vite fait:

→ matrice positive M. → décomposition Rt D R où D est diag ( = les vp[i] 
positives ) et R est la matrice orthonormé de changement de repère ( 
i.e. rotation ).

alors M^n = R^t D^n R

ta claim revient a dire que vp[i]^n = vp[i] * 10^(2(n-1))
et donc que les vp sont soit nulles, soit égales à 10^(2(n-1)/(n-1)) 
c'est à dire 100.




-- 
Fabrice