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From: robby <me@plan.net.ivalid>
Newsgroups: fr.sci.maths
Subject: =?UTF-8?B?UmU6IFLDqXNvdWRyZSBjZXR0ZSDDqWdhbGl0w6k=?=
Date: Tue, 6 Jun 2023 08:57:59 +0200
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Le 06/06/2023 à 08:37, Jacques Mathon a écrit :
> Je vois juste que X-10 doit diviser 10X
> Ce qui est bien le cas pour 14 (ainsi que pour 11,12,15 et 20)

argh, oui.

bon, raisonnement amélioré:

posons i := X-10   → y = 10(i+10)/i = 10 + 100/i
100 = 2²5²  donc i = 1,2,4,5,10,20,25,50,100
soit X = 11,12,14,15,20,30,35,60,110

-- 
Fabrice