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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_Analysis_of_Flibble=E2=80=99s_Latest=3A_Detecting_v?=
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Date: Mon, 26 May 2025 12:29:19 -0500
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On 5/26/2025 12:25 PM, Richard Heathfield wrote:
> On 26/05/2025 17:24, olcott wrote:
>> On 5/26/2025 11:10 AM, Richard Heathfield wrote:
>>> On 26/05/2025 16:42, olcott wrote:
>>>> no
>>>> C function can see its own caller.
>>>
>>> So because DDD calls HHH, HHH can't analyse the halting behaviour of 
>>> DDD.
>>>
>>> Got it.
>>>
>>
>> I didn't say that.
> 
> Yes, you did.
> 
> On 24/5/2025 in Message-ID <100sr6o$ppn2$3@dont-email.me> you said:
> 
>> You are a damned liar when you say that I said
>> that HHH must report on the behavior of its caller.
>>
>> No HHH can report on the behavior of its caller
>> for the same reason that no function can report
>> on the value of the square-root of a dead cat.
> 
> Your words.
> 
> Since DDD is HHH's caller, according to you HHH can't report on DDD's 
> behaviour.

HHH(DDD) does correctly report on the behavior that its
input specifies.

_DDD()
[00002192] 55             push ebp
[00002193] 8bec           mov ebp,esp
[00002195] 6892210000     push 00002192
[0000219a] e833f4ffff     call 000015d2  // call HHH
[0000219f] 83c404         add esp,+04
[000021a2] 5d             pop ebp
[000021a3] c3             ret
Size in bytes:(0018) [000021a3]

How many recursive emulations does HHH have to
wait before its emulated DDD magically halts
on its own without ever needing to be aborted?


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer