Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail
From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Incorrect requirements --- Computing the mapping from the input
 to HHH(DD)
Date: Fri, 9 May 2025 10:59:17 -0500
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In-Reply-To: <vvkg76$2m36t$5@dont-email.me>

On 5/9/2025 4:00 AM, Fred. Zwarts wrote:
> Op 09.mei.2025 om 02:05 schreef olcott:
>> On 5/8/2025 6:54 PM, Keith Thompson wrote:
>>> olcott <polcott333@gmail.com> writes:
>>>> On 5/8/2025 6:30 PM, Richard Heathfield wrote:
>>>>> On 08/05/2025 23:50, olcott wrote:
>>> [...]
>>>>>> If you are a competent C programmer
>>>>> Keith Thompson is a highly-respected and very competent C
>>>>> programmer.
>>>>
>>>> *Then he is just who I need*
>>>
>>> No, what you need is someone who is an expert in mathematical logic
>>> (I am not) who can explain to you, in terms you can understand and
>>> accept, where you've gone wrong.  Some expertise in C could also
>>> be helpful.
>>>
>>
>> The key gap in my proof is that none of the comp.sci
>> people seems to have a slight clue about simple C
>> programming.
>>
>> void DDD()
>> {
>>    HHH(DDD);
>>    return;
>> }
>>
>> *THIS IS THE C PART THAT NO ONE HERE UNDERSTANDS*
>> DDD correctly simulated by HHH cannot possibly
>> reach its own "return" instruction.
> 
> The HHH that you propose and is included in DDD does halt. But it is 
> known that this HHH prematurely aborts which makes it impossible for the 
> simulation to reach the reachable 'return'. HHH simply ignores the 
> conditional abort in the simulation.
> 

void DDD()
{
   HHH(DDD);
   return;
}

When 1 or more statements of DDD are correctly
simulated by HHH then this correctly simulated
DDD cannot possibly reach its own “return statement”.



-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer