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From: "Fred. Zwarts"
Newsgroups: comp.theory
Subject: Re: Who here is too stupid to know that DDD correctly simulated by
HHH cannot possibly reach its own return instruction?
Date: Wed, 7 Aug 2024 10:18:52 +0200
Organization: A noiseless patient Spider
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Op 04.aug.2024 om 21:00 schreef olcott:
> On 8/4/2024 1:54 PM, Richard Damon wrote:
>> On 8/4/24 9:11 AM, olcott wrote:
>>> On 8/4/2024 1:26 AM, Fred. Zwarts wrote:
>>>> Op 03.aug.2024 om 17:20 schreef olcott:>>
>>>>> When you try to show how DDD simulated by HHH does
>>>>> reach its "return" instruction you must necessarily
>>>>> must fail unless you cheat by disagreeing with the
>>>>> semantics of C. That you fail to have a sufficient
>>>>> understanding of the semantics of C is less than no
>>>>> rebuttal what-so-ever.
>>>>
>>>> Fortunately that is not what I try, because I understand that HHH
>>>> cannot possibly simulate itself correctly.
>>>>
>>>
>>> void DDD()
>>> {
>>> HHH(DDD);
>>> return;
>>> }
>>>
>>> In other words when HHH simulates itself simulating DDD it
>>> is supposed to do something other than simulating itself
>>> simulating DDD ??? Do you expect it to make a cup of coffee?
>>>
>>
>> No, but to be correct it need to complete that to the end.
>>
>
> Saying this and knowing there is no end cannot possibly
> be construed as anything but intentional deception.
>
And what is saying that there is no end for a program that aborts and
halts after two cycles? Are you dreaming again of the non-aborting HHH
that does not halt? Dreams are no substitute for facts.