Path: ...!weretis.net!feeder9.news.weretis.net!news.nk.ca!rocksolid2!i2pn2.org!.POSTED!not-for-mail From: Richard Damon Newsgroups: sci.logic,sci.math Subject: Re: Replacement of Cardinality Date: Fri, 30 Aug 2024 09:01:41 -0400 Organization: i2pn2 (i2pn.org) Message-ID: References: MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Fri, 30 Aug 2024 13:01:41 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="254423"; mail-complaints-to="usenet@i2pn2.org" User-Agent: Mozilla Thunderbird Content-Language: en-US In-Reply-To: Bytes: 1945 Lines: 25 On 8/30/24 8:55 AM, WM wrote: > Le 29/08/2024 à 20:51, "Chris M. Thomasson" a écrit : >> On 8/29/2024 6:27 AM, WM wrote: >>> Le 29/08/2024 à 01:48, Richard Damon a écrit : > >>>> You just can't count them from the "end" that doesn't have an end. >>> >>> Why not? >> >> Because it does not have an end. > > 0 lies below the end. Hence there is an end, even if you cannot see it. > > Regards, WM > > No, there does not need to be an "end" for an infinite sequence in that sequence. 0 is not "below" the end, but IS the end for the unit fractions, as we can get as close to it as we want with a unit fraction. A sequence whose end is not in the sequence doesn't have an end in the sequence.