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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Any honest person that knows the x86 language can see... predict
 correctly
Date: Thu, 1 Aug 2024 10:50:29 -0500
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On 8/1/2024 10:44 AM, joes wrote:
> Am Thu, 01 Aug 2024 08:04:23 -0500 schrieb olcott:
>> On 8/1/2024 7:56 AM, Fred. Zwarts wrote:
>>> Op 01.aug.2024 om 13:51 schreef olcott:
>>>> On 8/1/2024 2:46 AM, Fred. Zwarts wrote:
>>>>> Op 01.aug.2024 om 05:51 schreef olcott:
>>>>>> On 7/31/2024 10:08 PM, wij wrote:
>>>>>>> On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
>>>>>>>>
>>>>>>>> It is not supposed to be a general solution to the halting
>>>>>>>> problem.
>>>>>>>> it only shows how the "impossible" input is correctly determined
>>>>>>>> to be non halting.
>>>>>>> But how do you determine it is non-halting?
>>>>>>> As I know you are even unable to define what 'halt' mean !!!
> 
>>>>>> If DDD correctly emulated by HHH cannot possibly reach its return
>>>>>> instruction then it never halts.
>>>>>>
>>>>> But a correct simulation is impossible.
>>>> When HHH does what-ever-the-hell the x86 semantics specifies then HHH
>>>> is correct.
>>> But since HHH deviates from the semantics of the x86 language (by
>>> skipping instructions of a halting  program) it is incorrect.
>>>
>> Only a freaking moron would believe that a non terminating input should
>> be simulated forever.

> I mean, how many iterations of an infinite loop can I skip simulating or
> how many do I have to simulate to get identical behaviour?
> 

When one disables the abort code then the cycle never stops.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer