Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: Richard Damon Newsgroups: sci.math Subject: Re: How many different unit fractions are lessorequal than all unit fractions? Date: Sat, 28 Sep 2024 07:12:27 -0400 Organization: i2pn2 (i2pn.org) Message-ID: <90348169ab3b4b500ddb2d0c339504fe5c57fa4b@i2pn2.org> References: <1aabd037-86bc-47bd-b402-f6b29c5c33e4@att.net> <298dcb6f-5f58-48b6-80e3-34260bf721f8@att.net> <283c426f-ab1c-4ef0-a06c-1bf7d28a2cfa@att.net> <6b50a171-8127-4ce6-9bd3-2dc213638e9b@att.net> <519db81b-4a4d-417d-8cd2-7fef5a342efd@att.net> <6704347e-2f99-40f2-887f-de93f6fdd659@tha.de> <8b3e744d-3419-40c3-a7c6-fe59edd528a9@tha.de> <851e9929-8ab7-49d1-b478-e65c61fba2e3@att.net> <57dcb3994f147ebe5799308cad2ae1c8ac57e891@i2pn2.org> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Sat, 28 Sep 2024 11:12:27 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="3850463"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird X-Spam-Checker-Version: SpamAssassin 4.0.0 Content-Language: en-US In-Reply-To: Bytes: 3109 Lines: 44 On 9/27/24 2:42 PM, WM wrote: > On 25.09.2024 18:39, joes wrote: >> Am Wed, 25 Sep 2024 17:51:56 +0200 schrieb WM: > >>> NUF(x) distinguishes all points. >> How does it distinguish dark points? > > By our mathematical knowledge about ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 Which means for any 1/n, there exist a 1/(n+1) that is smaller than it, and thus there is no smallest 1/n. > >>> NUF increases. At no point it can increase by more than 1. >> Right, and there is no point "next to" 0 > > There is a unit fraction next to 0. Nope. "Next To" isn't a property of that set. > >>> Even if most mathematicians are far too stupid to understand this, I >>> will repeat it on and on, maybe that sometime some will get it. >> You should try explaining it a different way. > > ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 > is invincible. Right, and thus, for *ANY* 1/n, there exist a 1/(n+1) that will be smaller than it. PERIOD. Since, one property of ℕ is that ∀n ∈ ℕ, the value n+1 exists, and (n+1) ∈ ℕ You ignore this FACT because it proves your wrong, showing that you are nothing but a STUPID LIAR. > > Regards, WM > >