Path: ...!weretis.net!feeder9.news.weretis.net!news.quux.org!eternal-september.org!feeder2.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: WM Newsgroups: sci.math Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers Date: Thu, 21 Nov 2024 12:50:19 +0100 Organization: A noiseless patient Spider Lines: 22 Message-ID: References: <87babad37e3024a0fb219567f6fb2b7c46ff5eb7@i2pn2.org> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Thu, 21 Nov 2024 12:50:20 +0100 (CET) Injection-Info: dont-email.me; posting-host="56fd42f3dbe31aee8233c4a1d22ff497"; logging-data="672270"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1/ZhwcpoVDA0dGFhfqS/MF+tptuPc7KeuA=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:I4CW6GpDWCkueyXCjTrBrB1m1Ws= Content-Language: en-US In-Reply-To: Bytes: 2724 On 21.11.2024 01:08, joes wrote: > Am Wed, 20 Nov 2024 19:42:41 +0100 schrieb WM: >> On 20.11.2024 19:18, joes wrote: >>> Am Wed, 20 Nov 2024 13:04:04 +0100 schrieb WM: >> >>>> Try to count to a natural number that has fewer successors than >>>> predecessors. Impossible. >>> Because there are no such numbers. >> All successors are natural numbers. > So? > >> If all can be counted, then no successors remain. > All at once or every single one? Counting concerns every single number. >> But every number that can >> be counted to has more successors than predecessors. > Every number, period. There is no number without successors. Then not all can be counted. Regards, WM