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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: 2N=E
Date: Fri, 1 Nov 2024 12:42:07 +0100
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On 01.11.2024 11:59, FromTheRafters wrote:
> WM used his keyboard to write :
>> On 31.10.2024 22:53, FromTheRafters wrote:
>>> WM pretended :
>>
>>>>> Our sets do not change.
>>>>
>>>> Then:
>>>> Multiplication of all infinitely many fractions of the open interval 
>>>> (0, 1) results in some fractions in (1, 2).
>>>> Multiplication of all infinitely many numbers of the open interval 
>>>> (0, ω) result in some numbers in (ω, ω*2).
>>>
>>> No, there are no finite numbers in the transfinites.
>>
>> Numbers like ω + 4 are in the infinite. But if all natural numbers are 
>> doubled, then numbers in the infinite are produced.
> 
> What makes you think so?

Simplest mathematics. Doubling increases the value. If all natnumbers 
are existing, then the greatest existing natnumber is existing too, then 
doubling it does not produce a natural number.

Actual infinity is not about variable sets!

Regards, WM