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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: 2N=E
Date: Fri, 25 Oct 2024 18:59:53 +0200
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On 25.10.2024 18:54, Jim Burns wrote:
> On 10/24/2024 10:29 AM, WM wrote:

> 
>> The set, when existing completely,
>> covers an interval, namely (0, ω).
>> When its density is halved
>> while the number of elements is constant,
>> then its extension is doubled.
> 
> No.
> ⟨0,1,...,n-1,n,n+1,...,n+n-1,n+n⟩ is finite.

The extension is doubled in this finite set here as well as in my 
infinite set.

Regards, WM