Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.logic
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Thu, 28 Nov 2024 13:20:53 +0100
Organization: A noiseless patient Spider
Lines: 16
Message-ID: <vi9n75$hepc$1@dont-email.me>
References: <31419fde-62b3-46f3-89f6-a48f1fe82bc0@att.net>
 <ffa63cb5-8898-4aa7-80eb-8b2c51c9986d@att.net> <vhkhun$28qt$1@dont-email.me>
 <vhmtph$j1ek$1@dont-email.me> <vhn1jk$jf6v$1@dont-email.me>
 <vhn3po$jvo1$1@dont-email.me> <vhn420$jf6v$3@dont-email.me>
 <vhpg51$13soc$1@dont-email.me> <vhpnrb$15239$1@dont-email.me>
 <vhs2gn$1kjtc$1@dont-email.me> <vhs4ue$1ku9t$1@dont-email.me>
 <vhv6or$280s6$1@dont-email.me> <vhvbjb$28n6o$1@dont-email.me>
 <vi1dbj$2moon$1@dont-email.me> <vi224l$2pgrd$1@dont-email.me>
 <vi4383$3csd4$2@dont-email.me> <vi4a6c$3dt4s$2@dont-email.me>
 <c5a03e73203e6409f6b50c25b84a22d8df0d210b@i2pn2.org>
 <vi4k5a$3fj1t$1@dont-email.me>
 <8b860c66587b6d5d18e565caddb42cc3d5bb813c@i2pn2.org>
 <vi4vg4$3hg8t$3@dont-email.me> <vi509b$3hqcp$1@dont-email.me>
 <vi56el$3is82$1@dont-email.me> <vi57p2$3j62u$1@dont-email.me>
 <vi6tu2$3v0dn$3@dont-email.me>
 <bedba0f79694c3adbbcb4eff22a28b9597ea1293@i2pn2.org>
 <vi7uam$5cmb$1@dont-email.me>
 <376546bee4809e20528e0e9481315611ec5c3848@i2pn2.org>
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8; format=flowed
Content-Transfer-Encoding: 7bit
Injection-Date: Thu, 28 Nov 2024 13:20:53 +0100 (CET)
Injection-Info: dont-email.me; posting-host="67cce382144bf1df261eb72066b481f0";
	logging-data="572204"; mail-complaints-to="abuse@eternal-september.org";	posting-account="U2FsdGVkX1/wb9uYjBcNKybOFXc9T8lGJjKteFmGu/Y="
User-Agent: Mozilla Thunderbird
Cancel-Lock: sha1:KC2x8gnn4vQApMOKiOC4qdvOXGc=
Content-Language: en-US
In-Reply-To: <376546bee4809e20528e0e9481315611ec5c3848@i2pn2.org>
Bytes: 2592

On 27.11.2024 22:20, Richard Damon wrote:
> On 11/27/24 3:09 PM, WM wrote:

>> It is completed! Every number 10n starts wit a black hat.
> 
> Right, and it gives that hat to n, so every number gets one.
> 
> And, 10n will get back a hat from 100n, so it still have one at the end.
> 
It seems so, but that is impossible. Up to every 10n, the interval 1, 2, 
3, ... 10n has a covering of 1/10 only. The limit of this sequence is 
1/10 too. And since this is true for all natural numbers, where should 
additional hats come from?

Regards, WM