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From: Bart <bc@freeuk.com>
Newsgroups: comp.lang.c
Subject: Re: question about linker
Date: Sat, 7 Dec 2024 00:30:34 +0000
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On 06/12/2024 22:30, Scott Lurndal wrote:
> Ike Naar <ike@sdf.org> writes:
>> On 2024-12-06, Bart <bc@freeuk.com> wrote:
>>> My language:
>>>
>>>     println =a,=b                  # 13 characters, 0 shifted
>>>
>>> (And that space is optional!) In C (assume the existence of stdio.h):
>>>
>>>     printf("A=%lld B=%f\n",a,b);   # ~28 characters, 8 shifted
>>>
>>> Enough said.
>>
>> Looks like a cherry-picked example.
>> How would this (slightly modified) C statement be notated in your language:
>>
>>     printf("a:%lld b:%g\n",a,b);
>>
>> ?
> 
> Or
> 
>     printf("a:%2$8.8lld b:%1$10.2g",b,a);

In this case I'd just write it like this:

      printf("a:%2$8.8lld b:%1$10.2g",b,a)

ie. calling printf via an FFI. It's marginally shorter than C since I 
don't need the semicolon.

However, your attempt to catch me out on something I might not support 
has backfired, since it doesn't work even in C. This program:

   #include <stdio.h>
   int main(void) {
       long long a = 123456789876543210;
       double b=1.0/3;
       printf("a:%2$8.8lld b:%1$10.2g",b,a);
   }

compiled with gcc 14.1 on Windows, produces:

   a:%2$8.8lld b:%1$10.2g

On WSL and gcc 9.x it works, sort of. (Matching the label in the format 
string with the $ value and the argument looks confusing.)

I'd typically do this stuff like this:

    const fmta = "8.8", fmtb = "10.2"

    fprint "a:# b:#", a:fmta, b:fmtb

Here I don't need to care what the exact types of a and b are. I mean, 
what goes in place of ? here:

    printf("%?", a+b*c);

Assume only that a, b, c are numeric types, which might be opaque types 
exported by some header.

Here's another issue:

   #include <stdio.h>
   int main(void) {
       int i=0;
       printf("%d %d %d", ++i, ++i, ++i);
   }

3 compilers give me output of 1,2,3; 3,2,1; and 3,3,3.

If I do 'print ++i, ++i, ++i', it gives me 1,2,3 always. (Because this 
print is not a function call.)