Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: Richard Damon Newsgroups: sci.math Subject: Re: How many different unit fractions are lessorequal than all unit fractions? (infinitary) Date: Thu, 31 Oct 2024 19:43:20 -0400 Organization: i2pn2 (i2pn.org) Message-ID: References: <6a90a2e2-a4fa-4a8d-83e9-2e451fa8dd51@att.net> <0e5fb47d-60f7-42bb-beec-4a9661c807da@tha.de> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Thu, 31 Oct 2024 23:43:20 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="369694"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird X-Spam-Checker-Version: SpamAssassin 4.0.0 Content-Language: en-US In-Reply-To: Bytes: 2913 Lines: 30 On 10/31/24 1:33 PM, WM wrote: > On 31.10.2024 12:36, Richard Damon wrote: >> On 10/31/24 5:31 AM, WM wrote: > >> The problem is functions don't "grow" at a point > > Step functions like NUF do. No, they change at a value. > >> NUF(x) has an infinite slope at x = 0, as the unit fractions have an >> accumulaton point there. > > Wrong. In spite of the accumulation point, all unit fractions exist at > different points separated by uncountably many points. The accumulation > point has only been invented when the facts were not clear. By the way > the accumulation point shows that dark numbers exist. Infinitely many > unit fractions cannot be distinguished. > > Regards, WM > Right, but there is no first point, so no point for NUF(x) to make a step to 1 at, only to infinity. Why do you think that all those points can't be distinguished. They all have a finite value, and thus all are distinguished. Your logic just can't handle them.