Path: ...!eternal-september.org!feeder2.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: Mikko Newsgroups: sci.logic Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary) Date: Sun, 17 Nov 2024 14:28:14 +0200 Organization: - Lines: 22 Message-ID: References: <03b90d6c-fff1-411d-9dec-1c5cc7058480@tha.de> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Sun, 17 Nov 2024 13:28:15 +0100 (CET) Injection-Info: dont-email.me; posting-host="e058962f5bbbe0cfa5264c5cf2a7e895"; logging-data="678882"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1/evaSSTnp9L3tSzo+5F489" User-Agent: Unison/2.2 Cancel-Lock: sha1:+qsf9hgOpnEIZn6a0fUbI6OVtQU= Bytes: 2596 On 2024-11-17 10:29:31 +0000, WM said: > Your J'(n) = (n/100 - 1/10, n/100 + 1/10) are 100 times more than mine. > For every reordering of a finite subset of my intervals J(n) the > relative covering remains constant, namely 1/5. > The analytical limit proves that the constant sequence 1/5, 1/5, 1/5, > ... has limit 1/5. This is the relative covering of the infinite set > and of every reordering. My J'(n) are your J(n) translated much as your translated J(n) except that they are not re-ordered. My J'(n) are as numerous as your J(n): there is one of each for every natural number n. Each my J'(n) has the same size as your corresponding J(n): 1/5. One more similarity is that neither is relevant to the subject. -- Mikko