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From: WM <wolfgang.mueckenheim@tha.de>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Thu, 26 Dec 2024 12:34:56 +0100
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On 24.12.2024 15:03, Richard Damon wrote:
> On 12/24/24 5:53 AM, WM wrote:

>> Of course not. There is a bijection {n} <--> E(n). No cardinal number 
>> ℵ₀ is involved.
>> > Except that both sets, this size of the Natural Numbers and the size of
> the set of E(n), are Aleph_0.

They are in bijection. Cantor uses all n, I use all E(n) and therefore 
all n too. You claimed that I did not. You were wrong.

Regards, WM