Path: ...!weretis.net!feeder9.news.weretis.net!news.nk.ca!rocksolid2!i2pn2.org!.POSTED!not-for-mail From: Richard Damon Newsgroups: sci.math Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary) Date: Mon, 16 Dec 2024 07:30:23 -0500 Organization: i2pn2 (i2pn.org) Message-ID: <9841582965470f629905a77010bc74daaacef75d@i2pn2.org> References: <35274130-ffa0-4d11-b634-f2feb3851416@tha.de> <2269c430b8dc0136dd243ca05ba534f8b351c736@i2pn2.org> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Mon, 16 Dec 2024 12:30:24 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="3134483"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird In-Reply-To: X-Spam-Checker-Version: SpamAssassin 4.0.0 Content-Language: en-US Bytes: 3665 Lines: 44 On 12/16/24 3:41 AM, WM wrote: > On 15.12.2024 21:32, joes wrote: >> Am Sun, 15 Dec 2024 12:25:26 +0100 schrieb WM: >>> On 15.12.2024 11:56, Mikko wrote: >>>> On 2024-12-14 08:53:19 +0000, WM said: >>> >>>>> Please refer to the simplest example I gave you on 2024-11-27: >>>>> The possibility of a bijection between the sets ℕ = {1, 2, 3, ...} and >>>>> D = {10n | n ∈ ℕ} is contradicted because for every interval (0, n] >>>>> the relative covering is not more than 1/10, and there are no further >>>>> numbers 10n beyond all natural numbers n. >>>> >>>> It is already proven that there is such bijection. What is proven >>>> cannot be contradicted unless you can prove that 1 = 2. >>> >>> What is proven under false (self-contradictory) premises can be shown to >>> be false. Here we have a limit of 1/10 from analysis and a limit of 0 >>> from set theory. That shows that if set theory is right, we have 1/10 = >>> 0 ==> 1 = 0 ==> 2 = 1. >> Which sequence do you get a limit of 0 from? > > Sorry, the limit of not indexed numbers is 9/10 according to analysis > and 0 according to set theory, resulting in 9/10 = 0. And that logic says that 1 is equal to 0. >> >>>>> The sequence 1/10, 1/10, 1/10, ... has limit 1/10. >>>> Irrelevant as the proof of the exitence of the bijection does not >>>> mention that sequence. >>> But the disproof of the bijection does. There is no reason to forbid >>> that sequence. >> That sequence does not appear in the bijection. > > Therefore people were unaware of its failure. YOU are unaware of YOUR failure as you have blown your brain out by your logic's explosion to smithereens, leaving behind your darkness. > > Regards, WM >> >