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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: Anyone with sufficient knowledge of C knows that DD specifies
 non-terminating behavior to HHH
Date: Mon, 10 Feb 2025 13:15:06 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Sun, 09 Feb 2025 13:57:46 -0600 schrieb olcott:
> On 2/9/2025 1:42 PM, joes wrote:
>> Am Sun, 09 Feb 2025 13:00:05 -0600 schrieb olcott:
>>> On 2/9/2025 12:47 PM, Fred. Zwarts wrote:
>>>> Op 09.feb.2025 om 17:49 schreef olcott:
>>>>> On 2/9/2025 10:43 AM, Fred. Zwarts wrote:
>>>>>> Op 09.feb.2025 om 17:37 schreef olcott:
>>>>>>> On 2/9/2025 9:53 AM, Fred. Zwarts wrote:
>>>>>>>> Op 09.feb.2025 om 16:15 schreef olcott:
>>>>>>>>> On 2/9/2025 2:09 AM, Fred. Zwarts wrote:
>>>>>>>>>> Op 09.feb.2025 om 07:04 schreef olcott:
>>>>>>>>>>> On 2/8/2025 3:49 PM, Fred. Zwarts wrote:
>>>>>>>>>>>> Op 08.feb.2025 om 15:43 schreef olcott:
>>>>>>>>>>>>> On 2/8/2025 3:54 AM, Fred. Zwarts wrote:
>>>>>>>>>>>>>> Op 08.feb.2025 om 00:13 schreef olcott:
>> 
>>>>>>>>> The input to HHH(DD) cannot possibly terminate normally.
>>>>>>>>> Referring to some other DD does not change this verfied fact.
>>>>>>>> That DD halts is a verified fact.
>>>>>>> The input to HHH(DD) DOES NOT HALT !!!
>>>>>> It is a verified fact that the finite string describes a halting
>>>>>> program. Du to a bug, HHH does not see that, because it
>>>>>> investigates only the first few instructions of DD. HHH is unable
>>>>>> to process the call from DD to HHH correctly.

>>>> Indeed, because HHH fails to simulate itself up to the end.
>>>> This is verified with:
>>>>          int main() {
>>>>            return HHH(main);
>>>>          }
>>> There is no simulating itself to the end with the above example
>>> either.
>>> Apparently you do not understand the basic notion of recursion very
>>> well.
>> That’s the point. HHH doesn’t terminate.
> Counter-factual.
Then why does it report non-halting on itself?

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.