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From: olcott
Newsgroups: comp.theory
Subject: Re: Incorrect requirements --- Computing the mapping from the input
to HHH(DD)
Date: Sun, 11 May 2025 21:46:47 -0500
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On 5/11/2025 9:38 PM, dbush wrote:
> On 5/11/2025 10:36 PM, olcott wrote:
>> On 5/11/2025 9:28 PM, dbush wrote:
>>> On 5/11/2025 10:14 PM, olcott wrote:
>>>> On 5/11/2025 8:59 PM, dbush wrote:
>>>>> On 5/11/2025 9:56 PM, olcott wrote:
>>>>>> On 5/11/2025 8:27 PM, Richard Damon wrote:
>>>>>>> On 5/11/25 8:48 PM, olcott wrote:
>>>>>>>> On 5/11/2025 7:38 PM, Mike Terry wrote:
>>>>>>>>> On 11/05/2025 18:11, Richard Heathfield wrote:
>>>>>>>>>> On 11/05/2025 17:44, olcott wrote:
>>>>>>>>>>> Any yes/no question where both yes and no are the
>>>>>>>>>>> wrong answer is an incorrect polar question.
>>>>>>>>>>
>>>>>>>>>> Either DD stops or it doesn't (once it's been hacked around to
>>>>>>>>>> get it to compile and after we've leeched out all the dodgy
>>>>>>>>>> programming).
>>>>>>>>>
>>>>>>>>> Done that. It still stops.
>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> If the computer cannot correctly decide whether or not DD halts,
>>>>>>>>>
>>>>>>>>> The decider says it doesn't stop..
>>>>>>>>>
>>>>>>>>>> we have an undecidable computation,
>>>>>>>>>
>>>>>>>>> No no, that doesn't make sense. DD stops, and there are lots
>>>>>>>>> of partial halt deciders that will decide that particular input
>>>>>>>>> correctly. PO's DD isn't "undecidable".
>>>>>>>>>
>>>>>>>>> No single computation can be undecidable, considered on its
>>>>>>>>> own! There are only two possibilities: it halts or it doesn't.
>>>>>>>>> In either case there is a decider which decides that /one
>>>>>>>>> specific input/ correctly. By extension, any finite number of
>>>>>>>>> computations is decidable - we just have a giant switch
>>>>>>>>> statement followed by returning halts/neverhalts as
>>>>>>>>> appropriate. If the input domain has just n inputs, there are
>>>>>>>>> 2^n trivial deciders that together cater for every combination
>>>>>>>>> of each input halting or never halting. One of those deciders
>>>>>>>>> is a correct decider for that (finite domain) problem.
>>>>>>>>>
>>>>>>>>> The HP is asking for a TM (or equiv.) that correctly decides
>>>>>>>>> EVERY (P,I) in its one finite algorithm. That is what is
>>>>>>>>> proven impossible. The trick of having a big switch statement
>>>>>>>>> no longer works because there are infinitely many possible inputs.
>>>>>>>>>
>>>>>>>>> Decidability for just one single input is trivial and not
>>>>>>>>> intersting.
>>>>>>>>>
>>>>>>>>>> and therefore some computations are undecidable, so Turing's
>>>>>>>>>> conclusion was right. Who knew? (Apart from practically
>>>>>>>>>> everybody else, I mean.)
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> Mike.
>>>>>>>>
>>>>>>>> DDD emulated by HHH according to the rules of
>>>>>>>> the computational language that DD is encoded
>>>>>>>> within already proves that the HP "impossible"
>>>>>>>> input specifies a non-halting sequence of
>>>>>>>> configurations.
>>>>>>>
>>>>>>> No it doesn't.
>>>>>>>
>>>>>>
>>>>>> _DDD()
>>>>>> [00002172] 55 push ebp ; housekeeping
>>>>>> [00002173] 8bec mov ebp,esp ; housekeeping
>>>>>> [00002175] 6872210000 push 00002172 ; push DDD
>>>>>> [0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
>>>>>> [0000217f] 83c404 add esp,+04
>>>>>> [00002182] 5d pop ebp
>>>>>> [00002183] c3 ret
>>>>>> Size in bytes:(0018) [00002183]
>>>>>>
>>>>>> Show all the steps of DDD emulated by simulating
>>>>>> termination analyzer HHH according to the rules
>>>>>> of the x86 language
>>>>>
>>>>> Which it doesn't do as you have admitted on the record:
>>>>>
>>>>
>>>> I am daring you to show what they should be.
>>>> You know you can't because you know you are a liar.
>>>>
>>>
>>> Category error. Algorithm HHH does one thing and one thing only.
>>> There is no "what it should be" because it *is* only one thing.
>>>
>>
>> Show the exact sequence of machine address steps of DDD
>> such that the DDD emulated by some HHH
>
> Changing the input is not allowed.
There is no change of input you are a liar.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer