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From: vallor <vallor@cultnix.org>
Newsgroups: comp.lang.c
Subject: Re: Rationale for aligning data on even bytes in a Unix shell file?
Date: Mon, 28 Apr 2025 01:21:39 -0000 (UTC)
Organization: A noiseless patient Spider
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On Mon, 28 Apr 2025 02:53:45 +0200, Bonita Montero
<Bonita.Montero@gmail.com> wrote in
<vumjhf$20u1e$1@raubtier-asyl.eternal-september.org>:

> Am 27.04.2025 um 21:55 schrieb Janis Papanagnou:
> 
>> I think we have to distinguish the technical base size, an octet,
>> from the actual filenames. My Linux has no problem to represent,
>> say, filenames in Chinese or German umlaut characters that require
>> for representation 2 octets.
> 
> You're joking. Which applications currently can handle more than
> a 7 bit characters with Unix files ?

_[/home/vallor/tmp]_(vallor@lm)🐧_
$ touch 調和
_[/home/vallor/tmp]_(vallor@lm)🐧_
$ ls
調和
_[/home/vallor/tmp]_(vallor@lm)🐧_
$ ls -l
total 0
-rw-rw-r-- 1 vallor vallor 0 Apr 27 17:59 調和

ObC (What did I mess up here?):

$ cat readit.c 
#include <stdio.h>
#include <sys/types.h>
#include <dirent.h>
#include <string.h>

int main(void)
{
DIR * this = {0};
struct dirent * entry = {0};
char * s;

this = opendir(".");
while ((entry = readdir(this))!=NULL)
    {
    if(!strcmp(entry->d_name,".")) continue;
    if(!strcmp(entry->d_name,"..")) continue;
    for(s = entry->d_name; *s ; s++)
        {
        printf("%x\n",*s);
        }
    puts("---");
    }

return 0;
}

-- 
-v