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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: DDD simulated by HHH cannot possibly halt (Halting Problem)
Date: Fri, 11 Apr 2025 10:57:32 +0300
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On 2025-04-10 23:08:02 +0000, olcott said:

> On 4/10/2025 2:56 AM, Mikko wrote:
>> On 2025-04-09 20:35:30 +0000, olcott said:
>> 
>>> On 4/9/2025 1:58 PM, Fred. Zwarts wrote:
>>>> Op 09.apr.2025 om 19:29 schreef olcott:
>>>>> 
>>>>> On 4/8/2025 10:31 AM, Fred. Zwarts wrote:
>>>>>> Op 08.apr.2025 om 17:13 schreef olcott:
>>>>>>> On 4/8/2025 2:45 AM, Fred. Zwarts wrote:
>>>>>>>> Op 08.apr.2025 om 06:33 schreef olcott:
>>>>>>>>> 
>>>>>>>>> typedef void (*ptr)();
>>>>>>>>> int HHH(ptr P);
>>>>>>>>> 
>>>>>>>>> int DD()
>>>>>>>>> {
>>>>>>>>>    int Halt_Status = HHH(DD);
>>>>>>>>>    if (Halt_Status)
>>>>>>>>>      HERE: goto HERE;
>>>>>>>>>    return Halt_Status;
>>>>>>>>> }
>>>>>>>>> 
>>>>>>>>> int main()
>>>>>>>>> {
>>>>>>>>>    HHH(DD);
>>>>>>>>> }
>>>>>>>>> 
>>>>>>>>> *Simulating termination analyzer Principle*
>>>>>>>>> It is always correct for any simulating termination
>>>>>>>>> analyzer to stop simulating and reject any input that
>>>>>>>>> would otherwise prevent its own termination.
>>>>>>>> 
>>>>>>>> 
>>>>>>>> In this case there is nothing to prevent, because the finite string 
>>>>>>>> specifies a program that halts.
>>>>>>> 
>>>>>>> int DD()
>>>>>>> {
>>>>>>>    int Halt_Status = HHH(DD);
>>>>>>>    if (Halt_Status)
>>>>>>>      HERE: goto HERE;
>>>>>>>    return Halt_Status;
>>>>>>> }
>>>>>>> 
>>>>>>> This stuff is simply over-your-head.
>>>>>>> HHH(DD) meets the above: *Simulating termination analyzer Principle*
>>>>>>> Anyone with sufficient competence with the C programming language
>>>>>>> will understand this.
>>>>>>> 
>>>>>> Everyone with a little bit of C knowledge understands that if HHH 
>>>>>> returns with a value 0, then DDD halts.
>>>>> 
>>>>> DDD CORRECTLY SIMULATED BY HHH
>>>>> NOT ANY OTHER DAMN DDD IN THE UNIVERSE NITWIT.
>>>>> 
>>>> If HHH would correctly simulate DD (and the functions called by DD) 
>>>> then the simulated HHH would return to DD and DD would halt.
>>> 
>>> Simply over your level of technical competence.
>>> 
>>>> But HHH failed to complete the simulation of the halting program,
>>> 
>>> HHH is only required to report on the behavior of its
>>> own correct simulation (meaning the according to the
>>> semantics of the C programming language) and would be
>>> incorrect to report on any other behavior.
>>> 
>>>> because the programmer was dreaming of an infinite recursion.
>>>> 
>>>> If I didn't have to tell you this hundreds of times and you didn't
>>>> persist in the straw-man deception I would not have called you a nitwit.
>>>> 
>>>> 
>>> 
>>> I really think that you may simply be a troll playing head games.
>> 
>> It is not a good idea to think that everybody is just like you.
> 
> *Simulating termination analyzer Principle*
> It is always correct for any simulating termination
> analyzer to stop simulating and reject any input that
> would otherwise prevent its own termination.

No proof of this principle has been shown so its use is not valid.

-- 
Mikko