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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,comp.ai.philosophy,sci.logic
Subject: Re: The execution trace of HHH1(DDD) shows the divergence
Date: Sat, 7 Jun 2025 09:58:42 -0500
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On 6/7/2025 9:56 AM, dbush wrote:
> On 6/7/2025 10:54 AM, olcott wrote:
>> On 6/7/2025 9:51 AM, dbush wrote:
>>> On 6/7/2025 10:32 AM, olcott wrote:
>>>> The execution trace of HHH1(DDD) shows the divergence
>>>> of DDD emulated by HHH from DDD emulated by HHH1.
>>>>
>>>> int main()
>>>> {
>>>>    HHH1(DDD);
>>>> }
>>>>
>>>> Shows that DDD emulated by HHH and DDD emulated by
>>>> HHH1 diverges as soon as HHH begins emulating itself
>>>> emulating DDD.
>>>>
>>>> *From the execution trace of HHH1(DDD) shown below*
>>>> DDD emulated by HHH1              DDD emulated by HHH
>>>> [00002183] push ebp               [00002183] push ebp
>>>> [00002184] mov ebp,esp            [00002184] mov ebp,esp
>>>> [00002186] push 00002183 ; DDD    [00002186] push 00002183 ; DDD
>>>> [0000218b] call 000015c3 ; HHH    [0000218b] call 000015c3 ; HHH
>>>> *HHH1 emulates DDD once then HHH emulates DDD once, these match*
>>>>
>>>> The next instruction of DDD that HHH emulates is at
>>>> the machine address of 00002183.
>>>>
>>>> The next instruction of DDD that HHH1 emulates is at
>>>> the machine address of 00002190.
>>>
>>> False.
>>>
>>> The next instruction of DDD that both HHH and HHH1 emulates is at the 
>>> machine address of 000015c3, 
>>
>> *That is not an instruction of DDD*
>> *That is not an instruction of DDD*
>> *That is not an instruction of DDD*
>> *That is not an instruction of DDD*
> 
> In other words, you're not operating on algorithms.

In other words you are not actually paying any attention.


-- 
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer