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Subject: Entre i et -i.
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From: Richard Hachel
Euler pose e^i.π + 1 = 0
Bon, d'accord.
Et si je pose e^(-i)π + 1 = 0
Cela change quoi?
Et si je pose e^i.(-π) + 1 = 0 ?
ou e^(-i)(-π) + 1 = 0 ?
Tout cela reste-t-il invariant?
R.H.