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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: How do simulating termination analyzers work? ---Truth Maker
 Maximalism
Date: Fri, 4 Jul 2025 18:23:32 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Fri, 04 Jul 2025 12:30:43 -0500 schrieb olcott:
> On 7/4/2025 8:37 AM, joes wrote:
>> Am Fri, 04 Jul 2025 07:16:23 -0500 schrieb olcott:
>>> On 7/4/2025 3:55 AM, joes wrote:
>>>> Am Thu, 03 Jul 2025 17:11:45 -0500 schrieb olcott:
>>>>> On 7/2/2025 1:53 AM, Mikko wrote:
>>>>>> On 2025-07-01 11:46:11 +0000, olcott said:

>>>> You are effectively saying that all programs that start with a call
>>>> to HHH are the same.
Did I misunderstand you?

>>> Because it is not an input it HHH is not accountable for its behavior.
>>> Deciders are only accountable for computing the mapping from their
>>> inputs.
>> Yes it is, HHH should compute whether the code of DD halts when run.
>> You can't be thinking that is uncomputable.
> Likewise we should also compute the area of a square circle with a
> radius of 2.
Are you seriously suggesting that you can't compute what the code of
DDD does when executed?

> Partial halt deciders have never been allowed to report on the behavior
> of any directly executed Turing machine. Instead of this they have used
> the behavior that their input machine description specifies as a proxy.
And you think that DDD's direct execution is not specified by its
description?


> Now for the first time we see that DDD correctly simulated by HHH *IS
> NOT A PROXY* for the behavior of the directly executed DDD().
Indeed, HHH does not simulate it correctly. (You can't mean that DDD
is *executed* incorrectly.)

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.